An independent survey claimed that the average number of people who will vote for BBM in Visayas is greater than the average number of people who will vote for VPLR in Luzon. To validate this survey, a group of researchers conducted a post-test.In a survey of 210 people in Luzon, the average number of people who will vote for VPLR is 153 with a population standard deviation of 7.6. In a survey of 200 people in Visayas, the average number of people who will vote for BBM is 155 with a population standard deviation of 12.6. At α = 0.05, can people trust the result of the survey? What is the decision?Reject HoDo not Reject HoWhat does the decision imply?There is sufficient evidence at 95% level of confidence that the average number ofpeople who will vote for BBM in Visayas is greater than the number of people who willvote for VPLR in LuzonThere is no sufficient evidence at 95% level of confidence that the average number ofpeople who will vote for BBM in Visayas is greater than the number of people who willvote for VPLR in LuzonThere is sufficient evidence at 95% level of confidence that the average number ofO people who will vote for BBM in Visayas is not equal the number of people who willvote for VPLR in Luzon What test should be used in the case analysis?Two-sample Test Hypothesis Testing (t-test for Mean)Two-sample Test Hypothesis Testing (Z-test for Population Proportion)Two-sample Test Hypothesis Testing (Z-test for Mean)None of the choicesWhat is the critical value?1.9601.2821.6452.580What is the standard test statistic?1.41301.28202.16503.1250

Given Data : For Sample 1 x̄1 = 155.0 σ1 = 12.6 n1 = 200 For Sample 2…

An independent survey claimed that the average number of people who will vote for BBM in Visayas is greater than the average number of people who will vote for VPLR in Luzon. To validate this survey, a group of researchers conducted a post-test. In a survey of 210 people in Luzon, the average number of people who will vote for VPLR is 153 with a population standard deviation of 7.6. In a survey of 200 people in Visayas, the average number of people who will vote for BBM is 155 with a population standard deviation of 12.6. At α = 0.05, can people trust the result of the survey?

An independent survey claimed that the average number of people who will vote for BBM in Visayas is greater than the average number of people who will vote for VPLR in Luzon. To validate this survey, a group of researchers conducted a post-test. In a survey of 210 people in Luzon, the average number of people who will vote for VPLR is 153 with a population standard deviation of 7.6. In a survey of 200 people in Visayas, the average number of people who will vote for BBM is 155 with a population standard deviation of 12.6. At α = 0.05, can people trust the result of the survey?

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

The U.S Navy requires that fighter pilots have heights between 64 inches and 74 inches. The Men’s are normally distributed with a mean of 68.6 inches andthe standard deviation of 2.8 inches. a) Find the percentage of men meeting the height requirement b) If the Air Force height requirements are changed to exclude only the tallest 4% and the shortest 4% of men, what are the new height requirements?
An ordinary traveler claims that the average difference between the plane fares of all trips from the Philippines to a certain destination in the two airlines is significantly different. To validate this claim, 145 trips have been randomly selected from the first airline, which gave a mean fare of PHP 23,502.71 with a sample standard deviation of PHP 4,853.39. On the other hand, 123 trips are chosen at random from the second airline, which provided a mean fare of PHP 21,884.09 with a sample standard deviation of PHP 4,987.73. Assume that the populations are normally distributed, and the standard deviations for both populations are equal. At ? = 0.01, indicate whether or not there is sufficient evidence to support the traveler’s claim
The mean attention span for a ten-year-old in the USA is 19.10 minutes with a standard deviation of 2.03 minutes. Dr. Nintendoaddict think that video game playing may increase attention span. Dr. Nintendoaddict surveys 25 ten-year-olds who regularly play video games and measure their attention span. Dr Nintendoaddict find that the video game players’ mean attention span is 20.85 minutes with a standard deviation of 2.45 minutes. What is the critical value of z for alpha = .05?
The owners of the Metro Cash & Carry wished to study customers’ shopping habits. From earlier studies, the owners were under the impression that a typical shopper spends 0.7 hour at the mall, with a standard deviation of 0.10 hour. Recently the owners added some specialty restaurants designed to keep shoppers in the mall longer. A research team was hired to evaluate the effects of the restaurants. A sample of 45 shoppers by the team revealed that the mean time spent in the mall had increased to 0.80 hour. i. Develop a hypothesis test to determine if the mean time spent in the mall changed. Use the .10 significance level. ii. Suppose the mean shopping time actually increased from 0.75 hour to 0.79 hours. What is the probability of making a Type II error? iii)When research team reported the information in part (b) to the mall owners, the owners believed that the probability of making a Type II error was too high. How could this probability be reduced? plz sove it…
According to a leasing firm's reports, the mean number of miles driven annually in its leased cars is 13,480 miles with a standard deviation of 1240 miles. The company recently starting using new contracts which require customers to have the cars serviced at their own expense. The company's owner believes the mean number of miles driven annually under the new contracts, H, is less than 13,480 miles. He takes a random sample of 80 cars under the new contracts. The cars in the sample had a mean of L3,280 annual miles driven. Is there support for the claim, at the 0.01 level of significance, that the population mean number of miles driven annually by cars under the new contracts, is less than 13,480 miles? Assume that the population standard deviation of miles driven annually was not affected by the change to the contracts. Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified…
In the 2000 census, the so-called 'short form' contained only 7 questions, including name, gender, age, race, how the person is related to the head of household, whether they are Hispanic, and whether they own or rent their home. According to U.S. Census Bureau, the average time to complete the short form is 10 minutes. Assuming a standard deviation of 2 minutes and a simple random sample of 30 persons who completed the short form, does it seem very likely that the members of such a sample would have required an average of 8 minutes or less to
At EM Industries a certain machine fills 2-pound (32 ounces) boxes with cereal. The machine’s actual fill amount for the 2-pound box is found to have an average of 31.9 ounces and standard deviation of 0.40 ounces. If a box has at least 31.5 ounces of cereal, it considered “acceptable” by the government office of food product regulation. If a box has more than 32.5 ounces of cereal, it is considered “over-filled” by operations managers at EM Industries. a) What is the probability that a randomly filled box is “acceptable”? What is the probability that a randomly selected box is both, at the same time, “acceptable” and NOT “over-filled”? b) To monitor the current performance of the box filling process, Mo Nerdstat, quality control manager, decides to measure 20 boxes an hour and track this average performance measure over time. Develop 3-sigma limits for the current average process and draw the associated averages control chart.
The Sony Corporation produces an AM/FM Walkman that requires two AA batteries. The mean life of these batteries is 35.0 hours. The distribution of the battery lives closely follows the normal distribution with a standard deviation of 5.5 hours. As a part of their testing programme, Sony tests samples of 25 batteries. a)What fraction of the sample will have a mean useful life of greater than 34.5 hours? b)What fraction of the sample will have a mean useful life between 34.5 and 36.0 hours?
A private college in Ohio wishes to determine whether or not students living on campus have similar GPA’s to commuter students. They survey 120 resident students and find an average GPA of 2.82, with a sample standard deviation of .71. They also survey 90 commuter students and find an average GPA of 2.65, with a sample standard deviation of .58. Test the claim that resident students and commuter students have the same average GPA, against the alternative that these GPA’s differ, using a = .02.