Test the claim that the proportion of men who own cats is significantly different than 40% at the 0.05 significance level. The null and alternative hypothesis would be: Ho:µ = 0.4 Ho:µ = 0.4 Ho:p= 0.4 Ho:p=0.4 Ho:p = 0.4 Ho:µ= 0.4 H1:µ < 0.4 H1:µ + 0.4 H1:p> 0.4 H1:p< 0.4 H1:p+0.4 H1:µ > 0.4 The test is: two-tailed right-tailed left-tailed Based on a sample of 55 people, 37% owned cats

Test the claim that the proportion of men who own cats is significantly different than 40% at the 0.05 significance level. The null and alternative hypothesis would be: Ho:µ = 0.4 Ho:µ = 0.4 Ho:p= 0.4 Ho:p=0.4 Ho:p = 0.4 Ho:µ= 0.4 H1:µ < 0.4 H1:µ + 0.4 H1:p> 0.4 H1:p< 0.4 H1:p+0.4 H1:µ > 0.4 The test is: two-tailed right-tailed left-tailed Based on a sample of 55 people, 37% owned cats

Name: Test the claim that the proportion of men who own cats is significant
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Test the claim that the proportion of men who own cats is significantly different than 40% at the 0.05significance level.The null and alternative hypothesis would be:Ho:µ = 0.4 Ho:µ = 0.4 Ho:p= 0.4 Ho:p = 0.4 Ho:p= 0.4 Ho:µ = 0.4H1:µ < 0.4 Hị:µ7 0.4

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.1 significance level.The null and alternative hypothesis would be: H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 H0:p≤0.8H0:p≤0.8H1:p>0.8H1:p>0.8 H0:p≥0.8H0:p≥0.8H1:p<0.8H1:p<0.8 H0:μ≤0.8H0:μ≤0.8H1:μ>0.8H1:μ>0.8 H0:μ≥0.8H0:μ≥0.8H1:μ<0.8H1:μ<0.8 The test is: right-tailed left-tailed two-tailed Based on a sample of 200 people, 87% owned catsThe p-value is:  (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Test the claim that the mean GPA of night students is larger than 3.2 at the .005 significance level.The null and alternative hypothesis would be: H0:p=0.8H1:p<0.8 H0:p=0.8H1:p>0.8 H0:μ=3.2H1:μ>3.2 H0:μ=3.2H1:μ≠3.2 H0:μ=3.2H1:μ<3.2 H0:p=0.8H1:p≠0.8 Based on a sample of 55 people, the sample mean GPA was 3.22 with a standard deviation of 0.03The test statistic is  (to 3 decimals)The critical value is  (to 3 decimals)Based on this we fail to reject the null hypothesis reject the null hypothesis
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .005 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF The test is: right-tailed left-tailed two-tailed Based on a sample of 80 men, 25% owned catsBased on a sample of 60 women, 30% owned catsThe test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
In 1990, the average duration of long-distance telephone calls originating in one town was 9.4 minutes. A long-distance telephone company wants to perform a significance test to determine whether the average duration of long-distance phone calls has changed from the 1990 mean of 9.4 minutes. The hypotheses are:                                H0: μ = 9.4 minutes                                HA: μ ≠ 9.4 minutesSuppose that the results of the sample lead to non-rejection of the null hypothesis. Classify that conclusion as a Type I error, a Type II error, or a correct decision, if in fact the mean duration of long-distance phone calls has changed from the 1990 mean of 9.4 minutes. Choose the best asnwer below: A. Neither B. Type I error C. Type II error D.No error
Test the claim that the proportion of men who own cats is smaller than 90% at the .05 significance level.The null and alternative hypothesis would be: H0:μ=0.9H0:μ=0.9H1:μ>0.9H1:μ>0.9 H0:p=0.9H0:p=0.9H1:p>0.9H1:p>0.9 H0:p=0.9H0:p=0.9H1:p≠0.9H1:p≠0.9 H0:μ=0.9H0:μ=0.9H1:μ≠0.9H1:μ≠0.9 H0:μ=0.9H0:μ=0.9H1:μ<0.9H1:μ<0.9 H0:p=0.9H0:p=0.9H1:p<0.9H1:p<0.9 The test is: right-tailed two-tailed left-tailed Based on a sample of 65 people, 87% owned catsThe test statistic is:  (to 2 decimals)The critical value is:  (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis I dont understand this.
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF The test is: two-tailed right-tailed left-tailed Based on a sample of 60 men, 30% owned catsBased on a sample of 40 women, 40% owned catsThe test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis Check AnswerQuestion 14
A researcher wants to test whether the mean height for men and women are different, using a significance level of 0.05. Which is the correct hypothesis? A Ho: P1 = P2 Ha: P1 P2 D Ho: P1 = μ2 Ha: H1 H2 O C A OF OE O B B Ho: P1 = P2 Ha: P1 P2 E Ho: P1 = μ2 Ha: 12 C Ho: P1 = P2 Ha: 1: P₁ P2 F H₂:₁ = 1₂ Ha: ₁ 2
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF The test is: left-tailed two-tailed right-tailed Based on a sample of 20 men, 40% owned catsBased on a sample of 40 women, 55% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of people who own cats is smaller than 60% at the 0.005 significance level.The null and alternative hypothesis would be: H0:μ=0.6H0:μ=0.6H1:μ≠0.6H1:μ≠0.6 H0:p=0.6H0:p=0.6H1:p≠0.6H1:p≠0.6 H0:p≤0.6H0:p≤0.6H1:p>0.6H1:p>0.6 H0:μ≥0.6H0:μ≥0.6H1:μ<0.6H1:μ<0.6 H0:p≥0.6H0:p≥0.6H1:p<0.6H1:p<0.6 H0:μ≤0.6H0:μ≤0.6H1:μ>0.6H1:μ>0.6 The test is: two-tailed right-tailed left-tailed Based on a sample of 200 people, 51% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Test the claim that the mean GPA of night students is larger than 3.3 at the .10 significance level.The null and alternative hypothesis would be: H0:μ=3.3H0:μ=3.3H1:μ>3.3H1:μ>3.3 H0:p=0.825H0:p=0.825H1:p<0.825H1:p<0.825 H0:p=0.825H0:p=0.825H1:p≠0.825H1:p≠0.825 H0:μ=3.3H0:μ=3.3H1:μ<3.3H1:μ<3.3 H0:μ=3.3H0:μ=3.3H1:μ≠3.3H1:μ≠3.3 H0:p=0.825H0:p=0.825H1:p>0.825H1:p>0.825 The test is: right-tailed two-tailed left-tailed Based on a sample of 80 people, the sample mean GPA was 3.35 with a standard deviation of 0.06The test statistic is: (to 2 decimals)The critical value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis Im not understanding this material.
Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.2 significance level. The null and alternative hypothesis would be: Ho: p= 0.8 Ho: ≤ 0.8 Hop: 0.8 Ho:p> 0.8 Ho: 0.8 Ho:p 0.8 H₁:µ 0.8 H₁:p 0.8 The test is: right-tailed two-tailed left-tailed = Based on a sample of 300 people, 82% owned cats The p-value is: (to 2 decimals)
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF The test is: right-tailed left-tailed two-tailed Based on a sample of 40 men, 25% owned catsBased on a sample of 20 women, 30% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis