Test the claim that the mean temperature (in degrees F) in Santa Maria is different than 69.2. A random sample of temperatures at 13 locations yields a mean temperature of 68.32 with a standard deviation of 1.1. Use a = 0.05. You may assume that temperatures are normally distributed. 1. The sample size restriction for this test is: O Need n > 30 O Need at least 5 successes and 5 failures None needed since population is normally distributed The hypotheses are: О Но:р - 69.2;B На:р + 69.2 Ο Ho: μ Σ 69.2, Ha: μ < 69.2 Ο Ho: μ - 69.2; Ha: μ# 69.2 O Ho:p < 69.2; Ha:p > 69.2 O Ho:p < 69.2; Ha:u > 69.2 O Ho:p > 69.2; Ha:p < 69.2 2. This is a O twoO rightO left tailed test and the distribution used is OZ since testing a proportion OT since o not known OZ since o known The Degrees of Freedom are O 13 ON/A since this is a Z-test O 12

Test the claim that the mean temperature (in degrees F) in Santa Maria is different than 69.2. A random sample of temperatures at 13 locations yields a mean temperature of 68.32 with a standard deviation of 1.1. Use a = 0.05. You may assume that temperatures are normally distributed. 1. The sample size restriction for this test is: O Need n > 30 O Need at least 5 successes and 5 failures None needed since population is normally distributed The hypotheses are: О Но:р - 69.2;B На:р + 69.2 Ο Ho: μ Σ 69.2, Ha: μ < 69.2 Ο Ho: μ - 69.2; Ha: μ# 69.2 O Ho:p < 69.2; Ha:p > 69.2 O Ho:p < 69.2; Ha:u > 69.2 O Ho:p > 69.2; Ha:p < 69.2 2. This is a O twoO rightO left tailed test and the distribution used is OZ since testing a proportion OT since o not known OZ since o known The Degrees of Freedom are O 13 ON/A since this is a Z-test O 12

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Bootstrapping is a helpful tool when A. the sample size is too small to get an accurate estimate B. the sample proportion is very close to 0 or 1 C. we want to estimate a standard deviation in any context D. we don't have technology nearby
Please help
Wheaties cereal is claimed to have an average of 3 grams of dietary fiber per serving. We want to test this hypothesis and to see whether we believe that is true or that the mean amount of fiber is significantly different from 3 grams. A random sample of 25 servings was taken and it yielded a sample mean of 3.4 grams with the sample standard deviation in the amount of fiber, s = .8 grams. %3D Assume that software has determined the p-value to be.02. Carry out the test at the 5% level of significance. Be sure to state your decision rule and your decision for the test. O Fail to Reject the null hypothesis since the p-value is .05 O Fail to Reject the null hypothesis since the p-value is > .05
Pls help ASAP. Pls show all work.
Answer number 3 to 5 pls. I don't want to waste my money here
n a trial for the university athletics competition, one aims to estimate the mean chest size of the male athletes. A random sample of 70 male athletes gave rise to an average chest size of 42 inches with a standard deviation of 16 inches. What would be the distribution of the statistic that we need to estimate the mean chest size? a. It is a normal distribution with mean 42 inches and standard deviation 16 inches. b. it is a student's t distribution with degree of freedom 69. c. It is a student's t distribution with mean 42 inches and standard deviation 16 inches. d. it is a normal distribution with degree of freedom 69. 2.What is the standard error of the sample mean in problem 1? a. 1.91 b. 0.23 c. 17.5 d. 16 3. What would be the margin of error for a 95% confidence interval of the true chest size in problem 1? a. 0.46 b. 0.52 c. 3.82 d. 4.38
This Is A REVIEW! Please help and show work on paper
I don't know how to do the blank questions
An IQ score has a Normal distribution with mean 50 and standard deviation 5. Assume we want a sample of size 9. What proportion of sample means (of size 9) are less than 46.1? (Select nearest answer if your exact answer is not provided below). Group of answer choices 0.16 0.05 0.01 0.0013
The overhead reach distances off adult female are normally distributed with a mean off 200 cm and a standard deviation of 8.6 cm a.Find the probability that an individual distance is greater than 209.30 cm d.Find the probability that the mean for 20 random selected distance is greater than 198.70 cm
Please SHOW ALL WORK and ensure the ANSWER is CORRECT. Thank you!
i have upload it. i will appreciate if you show all the step by step answer. thanks.