Wheaties cereal is claimed to have an average of 3 grams of dietary fiber perserving. We want to test this hypothesis and to see whether we believe that is trueor that the mean amount of fiber is significantly different from 3 grams. A randomsample of 25 servings was taken and it yielded a sample mean of 3.4 grams with thesample standard deviation in the amount of fiber, s = .8 grams.Assume that software has determined the p-value to be .02.What would your decision be on this hypothesis test if we use a level of significancefor the test of alpha = .01?O Fail to reject the null hypothesis at the 1% level of significance.O Reject the null hypothesis at the 1% level of significance.

Here given cereal is claimed to have an average of 3 grams of dietary fiber per serving Here test…

Answered: What would your decision be on this…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Q. 14 Distinguish between non-randomised and randomised test.
If you have a hypothesis test with alpha = 0.04, which of the following P-Values does NOT imply statistical significance? 0.015 0.008 0.034 0.175
Based on certain data, a null hypothesis is rejected atthe 0.05 level of significance. Would it also be rejectedat the(a) 0.01 level of significance;(b) 0.10 level of significance?
State the Result: A hypothesis test was conducted at the alpha = 0.01 level of significance. The test resulted in a p-value of 0.044.
Answer the following True or False: Suppose a hypothesis test was performed with a level of significance of 0.05. Then if the null hypothesis is actually true, then there is a 5% chance that the researcher will end up accepting the alternative hypothesis in error. false true
Three students, an athlete, a fraternity member, and an honors student, record the number of hours they slept each night for 20 nights. O JMP Applet imp ? Oneway Analysis of Sleep Hours By Student Oneway Analysis of Sleep Hours By Student 10 Oneway Anova 14 Summary of Fit 12 Rsquare 0.024506 10- Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00072 1.99517 7.7 60 Analysis of Variance Sum of Mean F Prob > Source DF Squares Square Ratio F 2 Athiete Frat Honors Student 2 5.70000 2.85000 0.7180 0.4931 Student Error 57 226.90000 3.98070 C. Total 59 232.60000 Oneway Anova Means for Oneway Anova Std Lower Upper 95% Summary of Fit Level Number Mean Error 95% Athlete 20 8.10000 0.44813 7.2086 8.9934 Rsquare 0.024506 Frat 20 7.65000 0.44813 6.7588 8.5434 Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00972 Honors 20 7.35000 0.44813 6.4586 8.2434 1.99517 Std Error uses a pooled estimate of error variance 7.7 60 Analysis of…
A professor notices that more and more students are using their laptop computers in class to take notes. He wonders if this may improve academic success. To test this, the professor records the number of times each student uses his or her laptop during a class for one semester (Laptop) and the final grade in the class out of 100 points (Grade). The professor wants to conduct a hypothesis test to test whether or not there is a significant relationship between Laptop and Grade at the .05 level of significance. Laptop Grade 30 86 23 88 6 94 0 56 24 78 36 72 10 80 0 90 0 82 8 60 12 84 18 74 0 78 32 66 36 54 12 98 8 81 18 74 22 70 38 90 5 85 29 93 26 67 10 80 Using excel, create a scatterplot and interpret. Does it seem to suggest there is a relationship? Write the null hypothesis and alternative hypothesis in symbols Using excel, obtain the correlation coefficient and report the output for the hypothesis test. Make a decision about…
If significance level=0.05 and p-value=0.07, do you reject or fail to reject the null hypothesis H0?
In 2018, a study was conducted that stated 22.6% of residents in Kern County live below the poverty line. Suppose you were hired to determine if that percentage has changed since the study was conducted. You randomly sample 200 residents from Kern County and find that 35 of them fall below the poverty line. Carry out the appropriate hypothesis test at the a = 0.05 level of significance to determine if the true proportion of Kern County residents that live below the poverty line is lower than what it was in 2018.
You are conducting a study to see if the probability of a true negative on a test for a certain cancer is significantly different from 0.27. You use a significance level of α=0.001. H0:p=0.27H0:p=0.27 H1:p≠0.27H1:p≠0.27You obtain a sample of size n=406n=406 in which there are 97 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the probability of a true negative on a test for a certain cancer is different from 0.27. There is not sufficient evidence to warrant rejection of the claim that the probability of a true negative on a test for a…

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What would your decision be on this hypothesis test if we use a level of significance for the test of alpha = .01?