Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the .05 significance level. 1. The null and alternative hypothesis would be: H0:pN=pD H1:pN>pD H0:μN=μD H1:μN>μD H0:μN=μD H1:μN≠μD H0:pN=pD H1:pN≠pD H0:μN=μD H1:μN<μD H0:pN=pD H1:pN -2.62 4. The critical value (CV) is (to 2 decimals): -2.022 => -2.02 5. Based on this we: -2.62 (TS) < -2.02 (CV) Fail to reject the null hypothesis Reject the null hypothesis
[All my answers are in BOLD & UNDERLINED, the rest are questions or information)
The main question I have about this problem is how to find the critical value, using ONLY the calculator. I asked my teacher for help and he told me to use the invT
Your help will be greatly appreciated!
Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the .05 significance level.
1. The null and alternative hypothesis would be:
H1:pN>pD
H1:μN≠μD
H1:pN≠pD
H1:μN<μD
H1:pN<pD
2. The test is:
The sample consisted of 45-night students, with a sample mean GPA of 3.47 and a standard deviation of 0.04, and 40-day students, with a sample, mean GPA of 3.49 and a standard deviation of 0.03.
3. The test statistic (TS) is (to 2 decimals): -2.624 => -2.62
4. The critical value (CV) is (to 2 decimals): -2.022 => -2.02
5. Based on this we: -2.62 (TS) < -2.02 (CV)
Fail to reject the null hypothesis
Reject the null hypothesis
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