Task: Remove all asterisks (*) in the codes and use typedef int* IntPtr instead, and make it run with the same output. Code: #include using namespace std; int main() { int *p1, *p2; p1= new int; *p1 = 42; p2 = p1; cout << "*p1 == " << *p1 << endl; cout << "*p2 == " << *p2 << endl; *p2 = 53; cout << "*p1 == " << *p1 << endl; cout << "*p2 == " << *p2 << endl; p1 = new int; *p1 = 88; cout << "*p1 == " << *p1 << endl; cout << "*p2 == " << *p2 << endl; return 0; }

Task: Remove all asterisks () in the codes and use typedef int IntPtr instead, and make it run with the same output. Code: #include using namespace std; int main() { int p1, p2; p1= new int; p1 = 42; p2 = p1; cout << "p1 == " << p1 << endl; cout << "p2 == " << p2 << endl; p2 = 53; cout << "p1 == " << p1 << endl; cout << "p2 == " << p2 << endl; p1 = new int; p1 = 88; cout << "p1 == " << p1 << endl; cout << "p2 == " << *p2 << endl; return 0; }

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

#include #include using namespace std; //function prototypesint countLetters(char*); int countDigits(char*); int countWhiteSpace(char*); int main() { int numLetters, numDigits, numWhiteSpace; char inputString[51]; cout <<"Enter a string of no more than 50 characters: " << endl << endl; cin.getline(inputString,51); numLetters = countLetters(inputString); numDigits = countDigits(inputString); numWhiteSpace = countWhiteSpace(inputString); cout << "The number of letters in the entered string is " << numLetters << endl; cout << "The number of digits in the entered string is " << numDigits << endl; cout << "The number of white spaces in the entered string is " << numWhiteSpace << endl; return 0; } int countLetters(char *strPtr) { int occurs = 0; while(*strPtr != '\0') // loop is executed as long as// the pointer strPtr does not point // to the null character which// marks the end of the string // isalpha determines…
//I need help debugging the C code below the image is what I was following for directions while doing the code// #include <stdio.h> #include <stdlib.h> struct employees { char name[20]; int ssn[9]; int yearBorn, salary; }; // function to read the employee data from the user void readEmployee(struct employees *emp) { printf("Enter name: "); gets(emp->name); printf("Enter ssn: "); for (int i = 0; i < 9; i++) scanf("%d", &emp->ssn[i]); printf("Enter birth year: "); scanf("%d", &emp->yearBorn); printf("Enter salary: "); scanf("%d", &emp->salary); } // function to create a pointer of employee type struct employees *createEmployee() { // creating the pointer struct employees *emp = malloc(sizeof(struct employees)); // function to read the data readEmployee(emp); // returning the data return emp; } // function to print the employee data to console void display(struct…
Finish the following code: void Divide (int dividend, int divisor, bool& error, float& result) // Set error to indicate if divisor is zero. // If no error, set result to dividend / divisor. { using namespace std; // For debugging cout << "Function Divide entered." << endl; cout << "Dividend = " << dividend << endl; cout << "Divisor = " << divisor << endl; //** // Rest of code goes here. //** // For debugging if (error) cout << "Error = true "; else cout << "Error = false "; cout << "and Result = " << result << endl; cout << "Function Divide terminated." << endl; }
int main(int argc, char **argv) { float *rainfall; float rain_today; // rainfall has been dynamically allocated space for a floating point number. // Both rainfall and rain today have been initialized in hidden code. // Assign the amount in rain_today to the space rainfall points to. return 0; }
1. Examine the following code segment. What will be printed?If there are any errors indicate the nature of the error. int a[8] ={16, 12, 10, 7, 15, 18, 17, 29}; int *ptr ; ptr = & a[ 5 ] ; for(int i = 0; i<= 4; i = i + 2) cout<<a[i]<<*( ptr + i )<<endl; cout<<” ”<<a[1]<<” ”<<*ptr<<” ”<<*ptr + 2<<” ”<<*(ptr + 3);