Task 4: Determinant There are several ways to compute the determinant of an n x n matrix. In this task, we ask you to implement a simple method that considers elements from the top row and their respective minors. The determinant of a matrix A, det(A) is given by an alternate sum of the products between each element of the top row with its minor. det(A) = As you notice, this is a recursive definition that can be easily implemented with recursion. You can use the following fact to define the base case. For any 1 x 1 matrix A = [a], 4 1 2 3 4 5231 2501 324 2 det(A) = |a| = a Requirement: You must only use pointers to maintain the matrices' data. a b C d e f g h i j k l m n 0 P Input & Output Your program should read input from the standard input. The first line of the input is n and each of the next n lines contain n integers aij (-1000 ≤ ajj ≤ 1000). The output of your program should be the value of the determinant accurate to 5 decimal places. Input: Output: |f g h| e g h e f h| e f g = aj k 1-bi k 1+ci j 1-di m 0 Pl m n PI jk n 0 Pl m n 0 -105.00000 Homework 3 4 Important: Your program should not leak any memory. Ssytem Skill

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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det.c

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

double compute_det(int **a, int n) {
  // implement this
  return 0.0;
}

/*
TEST: ./det < det.in
OUTPUT:
-105.00000
*/
int main(void) {
  // implement this
}

 

det.in

4
1 2 3 4
5 2 3 1
2 5 0 1
3 2 4 2

Task 4: Determinant
There are several ways to compute the determinant of an n × ʼn matrix. In this task, we ask you to
implement a simple method that considers elements from the top row and their respective minors. The
determinant of a matrix A, det(A) is given by an alternate sum of the products between each element of
the top row with its minor.
det(A) =
4
1 2 3 4
5 2 3 1
250 1
3242
a b
Output:
C d
|f g h| e g h
-⠀⠀⠀⠀⠀⠀
= aj k 1-bi k 1+cij 1-di
n 0 Pl m 0 Pl m n Pl m
-105.00000
Homework 3
e f g h
det(A) = |a| = a
Requirement: You must only use pointers to maintain the matrices' data.
i j k 1
m n 0 P
As you notice, this is a recursive definition that can be easily implemented with recursion. You can
use the following fact to define the base case.
For any 1 x 1 matrix A = [a],
Input & Output Your program should read input from the standard input. The first line of the input is
n and each of the next n lines contain n integers aij (-1000 ≤ aij ≤ 1000).
The output of your program should be the value of the determinant accurate to 5 decimal places.
Input:
e f h| e
4
f g
jk
0
Important: Your program should not leak any memory.
n
Ssytem Skill
Transcribed Image Text:Task 4: Determinant There are several ways to compute the determinant of an n × ʼn matrix. In this task, we ask you to implement a simple method that considers elements from the top row and their respective minors. The determinant of a matrix A, det(A) is given by an alternate sum of the products between each element of the top row with its minor. det(A) = 4 1 2 3 4 5 2 3 1 250 1 3242 a b Output: C d |f g h| e g h -⠀⠀⠀⠀⠀⠀ = aj k 1-bi k 1+cij 1-di n 0 Pl m 0 Pl m n Pl m -105.00000 Homework 3 e f g h det(A) = |a| = a Requirement: You must only use pointers to maintain the matrices' data. i j k 1 m n 0 P As you notice, this is a recursive definition that can be easily implemented with recursion. You can use the following fact to define the base case. For any 1 x 1 matrix A = [a], Input & Output Your program should read input from the standard input. The first line of the input is n and each of the next n lines contain n integers aij (-1000 ≤ aij ≤ 1000). The output of your program should be the value of the determinant accurate to 5 decimal places. Input: e f h| e 4 f g jk 0 Important: Your program should not leak any memory. n Ssytem Skill
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