Target due: 5/1/207. Perform the indicated goodness-of-fit test.You roll a die 48 times with the following results.Number 12345 6.Frequency 13|2 13 1 4 15Use a significance level of 0.05 to test the claim that the die is fair.Select the correct conclusion about the null hypothesis.Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claimthat the die is fair.Reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that thedie is fair.Reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim thatthe die is fair.Fail to reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim thatthe die is fair.

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Answered: Target due: 5/1/20 7. Perform the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use technology to find the P-value for the hypothesis test described below. The claim is that for a smartphone carrier's data speeds at airports, the mean is μ=18.00 Mbps. The sample size is n=12 and the test statistic is t=1.129. P-value= ____
Identify the null hypothesis, alternative hypothesis, test statistic, conclusion about the null hypothesis and final conclusion that addresses the original claim. The health of employees is monitored by periodically weighing them in. A sample of 54 employees has a mean weight of 183.9lbs. Assuming that σ is known to be 121.2lb, use a 0.10 significance level to test the claim that the population mean of all such employees' weights is less than 200lb.
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Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is µ> 98.6°F. The sample size isn=9 and the test statistic is t=2.568. P-value = (Round to three decimal places as needed.)
A study is designed to determine the effect of an office-training course on typing productivity. Fifteen typists who have not taken the course are randomly selected. The investigator assigns 20 pages of equally difficult text to be typed by each typist both before and after completing the training course. The investigator wants to find out whether the training course has reduced the number of errors by more than 10. Define d = Before − After. Significance level What conclusion should we reach if the p-value is 0.113?
P VALUE FOR THE TEST HYPOTHESIS
The test statistic in a right-tailed test is z=−1.83. Determine the P-value and decide whether, at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. The P-value is _____________ (Round to three decimal places as needed.) This P-value _____________________ (does not provide or provides) sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis because it is_____________ (greater than or less than) the significance level.
Determine the critical value(s) for a one-mean z-test. Draw a graph that illustrates your answer. A left-tailed test with a = 0.03. Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. The critical value(s) is (are) (Round to two decimal places as needed. Use a comma to separate answers as needed.) Choose the correct graph of the hypothesis test below. O A. O B. Reject Ho 0.015 Do not reject Ho 0.985 Rej. Ho 0.03 Do not reject Ho 0.94 T 0 Rej. Ho Q 0.03 /₂0 O C. Do not reject Ho W 0.97 Reject Ho 0.03
The p-value for a hypothesis test turns out to be 0.0534. At a 3% level of sigrnificance, what is the proper decision? O Reject Ho O Fail to reject Ho Check Answer e Type here to search
Describe type I and type II errors for a hypothesis test of the indicated claim. A furniture store claims that at least 40% of its new customers will return to buy their next piece of furniture. Describe the type I error. Choose the correct answer below. OA. A type I error will occur when the actual proportion of new customers who return to buy their next piece of furniture is at least 0.40, but you fail to reject Ho: p20.40. OB. A type I error will occur when the actual proportion of new customers who return to buy their next piece furniture is at least 0.40, but you reject Ho: p20.40. OC. A type I error will occur when the actual proportion of new customers who return to buy their next piece of furniture is no more than 0.40, but you reject Ho: p ≤ 0.40. OD. A type I error will occur when the actual proportion of new customers who return to buy their next piece f furniture is no more than 0.40, but you fail to reject Ho: p ≤0.40. Describe the type II error. Choose the correct answer…
The null hypothesis and the alternate hypothesis are: H: The frequencies are equal. H₁: The frequencies are not equal. Category fe ABC D 15 10 10 15 a. State the decision rule, using the 0.05 significance level. (Round your answer to 3 decimal places.) Reject Ho if chi-square > b. Compute the value of chi-square. (Round your answer to 2 decimal place.) Chi-square value

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