find the P-value for the hypothesis test described below.
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Use technology to find the P-value for the hypothesis test described below. The claim is that for a smartphone carrier's data speeds at airports, the
P-value= ____
Answer:
A smartphone carrier's data speed at airports, the mean is =18.00 Mbps. The sample size is n=12
The test statistics is t=1.129
Here Hypothesis test is
The test statistics is,
=1.129
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- In a study, a random sample of 20 adults rated the effectiveness of advertisements. Each adult rated an advertisement that lasted 30 or 60 seconds. The block design in the accompanying table shows these ratings (on a scale of 1 to 5, with 5 being extremely effective). Use a = 0.05 and a technology tool and the given block design to perform a two-way ANOVA test. Click the icon to view the block design and ratings. Determine the null and alternative hypotheses for the main effects. Select all that apply. O A. Ho: The length of the ad has no effect on the rating. B. Ho: The rating has no effect on the advertising medium. Ha: The rating has an effect on the advertising medium. Ha: The length of the ad has an effect on the rating. O c. Ho: The advertising medium has no effect on the rating. D. Ho: : The advertising medium has no effect on the length of the ad. Ha: The advertising medium has an effect on the rating. : The advertising medium has an effect on the length of the ad. Ha: length…Test the indicated claim about the means of two populations. Assume that the two samples are randomly selected, independent, the population standard deviations are not know and not considered equal. Subjects are given a creativity exercise on a computer with either a red background or a blue background. The scores are shown in the table. At the 0.01 significance level, test the claim that blue enhances performance on a creative task. Red Background Blue Background n1 = 41 n2 = 44 xˉx̄1 = 19.2 xˉx̄2 = 18.7 s1 = 0.88 s2 = 0.35 What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.)H0: Select an answer μ(blue) s₁² μ₂ p₂ p̂₁ σ₁² p μ₁ x̄₂ μ x̄₁ p₁ ? < ≥ ≠ ≤ = > Select an answer p₁ μ s₁² σ₁² μ₂ p₂ x̄₁ p̂₁ μ(red) μ₁ p x̄₂ H1: Select an answer x̄₁ x̄₂ p₁ μ₁ μ μ(blue) p p₂ σ₂² s₂² p̂₂ μ₂ ? ≤ < = ≥ ≠ > Select an answer σ₁² x̄₂ p₁ x̄₁ μ₁ p p₂ μ μ₂ p̂₁ s₁² μ(red) Original Claim = Select an answer H₁ H₀ df = Based on…Use the attached image to answer the question: Use the data above to construct a bivariate table and explore if there is an association between one’s education and attitudes toward cohabitation. Is there an association? Describe the pattern of association. Assuming that this is a random sample, test a hypothesis (use α = 0.01) that there is an association between one’s education and attitudes toward cohabitation in the population. Show all your work (state the hypotheses, find the critical value, compute the test statistics, state a conclusion) and write one sentence summarizing the results. (Extra-credit: find the p-value). Is this association weak, moderate or strong? Compute and interpret the appropriate statistic.
- Use the pulse rates in beats per minute (bpm) of a random sample of adult females listed in the data set available below to test the claim that the mean is less than 74 bpm. Use a 0.01 significance level. E Click the icon to view the pulse rate data. Pulse Rate Data Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? Pulse Rate (bpm) O A. Ho: H= 74 bpm H1: H 74 bpm 57 35 104 86 ОС. Но: и» 74 bpm H1: µ<74 bpm O D. Ho: H=74 bpm H1: µ+74 bpm 97 101 62 49 59 73 Determine the test statistic. 69 45 104 42 |(Round to two decimal places as needed.) 52 105 99 36 Determine the P-value. 74 54 (Round to three decimal places as needed.) 105 60 56 82 State the final conclusion that addresses the original claim. 88 75 52 59 V Ho. There is evidence to conclude that the mean of the population of pulse rates for adult females is V 74 bpm. 82 104 97 76 76 47 97 74 63 52 93 98 104 53 35 35 100 39 Click to select your answer(s). 58 41You are interested in investigating whether the type of computer a person primarily uses and the type of car they drive are dependent. The table below shows the results of a survey. α = 0.01 significance level. Sedan SUV Truck Tablet 100 95 60 Notebook 119 106 37 Desktop 112 103 27 The test-statistic for this data =_____ (Please show your answer to three decimal places.) The p-value for this sample =_____ (Please show your answer to four decimal places.)Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic and P-value.Test the claim that the mean age of the prison population in one city is less than 26 years. Sample data are summarized as n = 25, x = 24.4 years, and s = 9.2 years. Use a significance level of α = 0.05. Round answersto 3 decimal places.test statistic ____________ P-value _____________
- Treatment Placebo 3. H1 H2 table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. A study was done using a treatment group and a placebo group. The results are shown in the 27 40 In 2.39 2.65 0.95 0.57 a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? O A. Ho: H1 = H2 O B. Ho: H1H2 D. Ho: H1 H2 The test statistic, t, is (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) State the conclusion for the test. O A. Fail to reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the two samples are from populations with the same mean. O B. Reject the null hypothesis. There is not sufficient evidence to warrant rejection…Two samples were given the same task. One sample was put into a room painted red, and the pther was put into a blue room. Thier creativity was scored and recorded while completeing the task. Results are given below. Use a 0.05 significance level to test the claim that the samples from populations with the same standard deviation. Assume that all the measurements are met for this test. Red Room n=34 Xbar =15.92 s= 5.97 Blue Room n=36 Xbar= 12.95 s= 5.49 Is this a right, left or two-tailed test? What is the P-Value? Rounded to 3 decimals Write a conclusion about this test.Perform the following hypothesis test of a proportion: HO: p = 0.125 HA: p 0.125 The sample proportion is 0.1 based on a sample size of 95. Use a 10% significance level. The critical values of the test statistic that divide the rejection and non-rejection regions are what value?
- A sample mean, sample size, and population standard deviation are provided below. Use the one-mean z-test to perform the required hypothesis test at the 10% significance level. x=35, n=21, a=5, Ho: μ = 34, H₂: μ#34 The test statistic is z = (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) the null hypothesis. The data sufficient evidence to conclude that the mean isUse a significance level of a = 9 scores for which x = 3.1 and s = 0.6. Use the traditional method of testing hypotheses. 0.01 to test the claim that u > 2.85. The sample data consist ofThe accompanying data table lists the magnitudes of 50 earthquakes measured on the Richter scale. Test the claim that the population of earthquakes has a mean magnitude greater than 1.00. Use a 0.01 significance level. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, and conclusion for the test. Assume this is a simple random sample.