TABLE A-6 Critical Values of the Pearson Correlation Coefficient r a = .05 a = .01 4. .950 .999 5. .878 .959 6. .811 .917 .754 .875 .707 .666 criticel 8. 834 9. .798 value for... 10 .632 .765 11 .602 .735 a =.01 12 .576 .708 13 .553 .684 14 .532 .661 15 .514 .641 2.n=92 a=105 16 .497 .623 17 .482 .606 .468 456 .590 .575 18 19 561 505 .463 20 .444 .396 .361 335 25 30 35 .430 40 .312 .402 45 294 .378 50 .279 .361 60 .254 .330 70 .236 .220 .305 .286 80 90 .207 .269 100 .196 .256 NOTE:To test Ho: p = 0 against H: p # 0, reject Ho if the absolute value of r is greater

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Author:Amos Gilat
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I am not sure how to go about finding the critical value for example number 2 when the value is not on the table.
TABLE A-6
Critical Values of the
Pearson Correlation
Coefficient r
a = .05
a = .01
n
4
.950
.999
.878
.811
.959
.917
6.
.754
.875
.707
.666
criticel
8
.834
9.
.798
value for...
10
.632
.765
11
.602
.735
a = .01
.708
.684
.661
.641
12
.576
13
.553
14
.532
15
.514
2. n=92 a=105
.623
.606
.590
16
.497
17
.482
18
.468
19
456
575
.444
396
.561
.505
20
25
30
.361
.463
35
.335
.430
40
.312
.402
45
294
.378
.361
50
.279
60
.254
.330
.236
.220
70
.305
80
.286
90
.207
.269
100
.196
.256
NOTE: To test Ho: p = 0 against H: p + 0,
reject Ho if the absolute value of r is greater
than the critical value in the table.
Transcribed Image Text:TABLE A-6 Critical Values of the Pearson Correlation Coefficient r a = .05 a = .01 n 4 .950 .999 .878 .811 .959 .917 6. .754 .875 .707 .666 criticel 8 .834 9. .798 value for... 10 .632 .765 11 .602 .735 a = .01 .708 .684 .661 .641 12 .576 13 .553 14 .532 15 .514 2. n=92 a=105 .623 .606 .590 16 .497 17 .482 18 .468 19 456 575 .444 396 .561 .505 20 25 30 .361 .463 35 .335 .430 40 .312 .402 45 294 .378 .361 50 .279 60 .254 .330 .236 .220 70 .305 80 .286 90 .207 .269 100 .196 .256 NOTE: To test Ho: p = 0 against H: p + 0, reject Ho if the absolute value of r is greater than the critical value in the table.
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