TABLE 17.1 Standard Reduction Potentials at 25°C Reduction Half-Reaction (V) 2 F (nq) F(g) + 2e H;O,(ag) + 2 H*Caq) + 2 e MnO, lag) + 8 H"(ag) + 5e Clg) + 2e Cr,0,"(ag) + 14 H*(aq) + 6e Og) + 4 H*(aq) + 4e Bry() + 2e Ag*(aq) + e Fe"(ag) + e Ogg) + 2 H*(aq) + 2e Iyls) + 2e Og) + 2 H;O) + 4 e Cu*(ag) + 2 e Snt"(aq) + 2e 2.87 Weaker Stronger oxidizing 1.78 reducing 2 H;O) Mn(ag) + 4 H;O) 2 CHag) →2 Cr*cag) + 7 H;On - 2 H¿O) → 2 Brtag) Ag(s) Fe²*(aq) H;O,laq) agent 1.51 agent 1.36 1.33 1.23 1.09 0.80 0.77 0.70 0.54 4 OH"Gaq) » Cuts) → Sn°"(aq) 0.40 0.34 0.15 2 H*(aq) + 2 e H;(g) P (ag) + 2e Ni"(ag) + 2 e Cd"(ag) + 2e Fe"(ag) + 2e Zn"(ag) + 2e Pb(s) -0.13 Ni(s) -0.26 → Cd(s) → Fels) -0.40 -0.45 Zn(s) -0.76 2 H;O) + 2e Al(ag) + 3e Mg"(ag) + 2 e Na*(aq) + e Li'(ag) + e • H;(g) + 2OHnq) → Al(s) Mg(s) → Na(s) -0.83 -1.66 -2.37 Stronger reducing agent Weaker -2.71 oxidizing agent Li(s) -3.04 Using Table 17.1, find E° for 2 H 20( )→ 2 H 2( g) + O 2(5). -2.06 V -0.40 V -1.23 V -0.80 V
TABLE 17.1 Standard Reduction Potentials at 25°C Reduction Half-Reaction (V) 2 F (nq) F(g) + 2e H;O,(ag) + 2 H*Caq) + 2 e MnO, lag) + 8 H"(ag) + 5e Clg) + 2e Cr,0,"(ag) + 14 H*(aq) + 6e Og) + 4 H*(aq) + 4e Bry() + 2e Ag*(aq) + e Fe"(ag) + e Ogg) + 2 H*(aq) + 2e Iyls) + 2e Og) + 2 H;O) + 4 e Cu*(ag) + 2 e Snt"(aq) + 2e 2.87 Weaker Stronger oxidizing 1.78 reducing 2 H;O) Mn(ag) + 4 H;O) 2 CHag) →2 Cr*cag) + 7 H;On - 2 H¿O) → 2 Brtag) Ag(s) Fe²*(aq) H;O,laq) agent 1.51 agent 1.36 1.33 1.23 1.09 0.80 0.77 0.70 0.54 4 OH"Gaq) » Cuts) → Sn°"(aq) 0.40 0.34 0.15 2 H*(aq) + 2 e H;(g) P (ag) + 2e Ni"(ag) + 2 e Cd"(ag) + 2e Fe"(ag) + 2e Zn"(ag) + 2e Pb(s) -0.13 Ni(s) -0.26 → Cd(s) → Fels) -0.40 -0.45 Zn(s) -0.76 2 H;O) + 2e Al(ag) + 3e Mg"(ag) + 2 e Na*(aq) + e Li'(ag) + e • H;(g) + 2OHnq) → Al(s) Mg(s) → Na(s) -0.83 -1.66 -2.37 Stronger reducing agent Weaker -2.71 oxidizing agent Li(s) -3.04 Using Table 17.1, find E° for 2 H 20( )→ 2 H 2( g) + O 2(5). -2.06 V -0.40 V -1.23 V -0.80 V
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![TABLE 17.1 Standard Reduction Potentials at 25°C
E°
(V)
Reduction Half-Reaction
2 F (aq)
F(g) + 2e
H;O,(ag) + 2 H*(aq) + 2 e
MnO, lag) + 8 H"(ag) + 5e
Clg) + 2e
Cr,0,"(ag) + 14 H*(aq) + 6 e
Og) + 4 H*(aq) + 4e
Bry() + 2e
Ag*(ag) + e
Fe"(ag) + e
Og) + 2 H*(ag) + 2e
Iyls) + 2e
Og) + 2 H,O) + 4e
Cu*(ag) + 2 e
Snt"(ag) + 20
2.87
Weaker
Stronger
oxidizing
agent
reducing
2 H;OD
Mn"(ag) + 4 H,O)
2 CHag)
→2 Cr*cag) + 7 H;On
- 2 H¿O)
→ 2 Bríag)
Ag(s)
1.78
1.51
agent
1.36
1.33
1.23
1.09
0.80
0.77
H;O;laq)
0.70
0.54
4 OH"Gag)
0.40
» Cuts)
→ Sn°"(aq)
→ H;(g)
0.34
0.15
2 H*(ag) + 20
P (ag) + 2e
Ni"(ag) + 2 e
Cd" (ag) + 2e
Fe"(ag) + 2e
Zn"(ag) + 2e
Pb(s)
-0.13
Ni(s)
-0.26
» Cd(s)
→ Fets)
-0.40
-0.45
Zn(s)
-0.76
2 H;O) + 2e
• H;(g) + 2OHlnq)
-0.83
Al(ag) + 3e
Mg"(ag) + 2 e
Na*(ag) + e
Li"(ag) + e
Al(s)
-1.66
Mg(s)
→ Na(s)
-2.37
Weaker
Stronger
reducing
agent
-2.71
oxidizing
agent
Li(s)
-3.04
Using Table 17.1, find E° for 2 H 20( )→ 2 H 2( g) + O 2(5).
-2.06 V
-0.40 V
-1.23 V
-0.80 V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc3e671be-5699-41c7-ad14-09ef8165fba8%2F3d73ae67-b629-4dda-8d55-8b3fad9742e1%2F6jdar9h_processed.png&w=3840&q=75)
Transcribed Image Text:TABLE 17.1 Standard Reduction Potentials at 25°C
E°
(V)
Reduction Half-Reaction
2 F (aq)
F(g) + 2e
H;O,(ag) + 2 H*(aq) + 2 e
MnO, lag) + 8 H"(ag) + 5e
Clg) + 2e
Cr,0,"(ag) + 14 H*(aq) + 6 e
Og) + 4 H*(aq) + 4e
Bry() + 2e
Ag*(ag) + e
Fe"(ag) + e
Og) + 2 H*(ag) + 2e
Iyls) + 2e
Og) + 2 H,O) + 4e
Cu*(ag) + 2 e
Snt"(ag) + 20
2.87
Weaker
Stronger
oxidizing
agent
reducing
2 H;OD
Mn"(ag) + 4 H,O)
2 CHag)
→2 Cr*cag) + 7 H;On
- 2 H¿O)
→ 2 Bríag)
Ag(s)
1.78
1.51
agent
1.36
1.33
1.23
1.09
0.80
0.77
H;O;laq)
0.70
0.54
4 OH"Gag)
0.40
» Cuts)
→ Sn°"(aq)
→ H;(g)
0.34
0.15
2 H*(ag) + 20
P (ag) + 2e
Ni"(ag) + 2 e
Cd" (ag) + 2e
Fe"(ag) + 2e
Zn"(ag) + 2e
Pb(s)
-0.13
Ni(s)
-0.26
» Cd(s)
→ Fets)
-0.40
-0.45
Zn(s)
-0.76
2 H;O) + 2e
• H;(g) + 2OHlnq)
-0.83
Al(ag) + 3e
Mg"(ag) + 2 e
Na*(ag) + e
Li"(ag) + e
Al(s)
-1.66
Mg(s)
→ Na(s)
-2.37
Weaker
Stronger
reducing
agent
-2.71
oxidizing
agent
Li(s)
-3.04
Using Table 17.1, find E° for 2 H 20( )→ 2 H 2( g) + O 2(5).
-2.06 V
-0.40 V
-1.23 V
-0.80 V
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