T/2 = In(2)T.
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In the box below, show that the time it takes the voltage across a discharging capacitor to drop to one-half its initial value is also given by Eq.(5)
![T/2 = In(2)T.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4c328189-5198-42cc-892a-2736bfe26a0f%2F588b01a6-5e36-4db8-a49e-69ce0c7efbe0%2F88jx6ui.jpeg&w=3840&q=75)
![](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4c328189-5198-42cc-892a-2736bfe26a0f%2F588b01a6-5e36-4db8-a49e-69ce0c7efbe0%2Ff3x06ho.jpeg&w=3840&q=75)
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