where did he get the 0.693 from » tyet2 = 20.9 Hnstyp =0.693/Kk =0•6930.603/ 20.9K= 0. 033 hit"%3Dk = 3.3 X/0-2 hri!

Half life It is the time when the Concentration becomes half of the initial Concentration

Answered: t2 = 20.9 Hns typ = 0.603/K k = 0•693…

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t2 = 20.9 Hns typ = 0.603/K k = 0•693 O: 693/20.9 0.693 K = E a.033 br

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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where did he get the 0.693 from

» tye
t2 = 20.9 Hns
typ =
0.693/K
k =
0•693
0.603/ 20.9
K
= 0. 033 hit"
%3D
k = 3.3 X/0-2 hri!

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