T(1,1)= (5,0) Let T:02 →0² be defined as, T (1,0) =(2,6) Then, T(3,2)=(11,12) (а) Т(),1) %3 (5,5) b) T(0,1)=(6,6) (c) T(0,1)=(7,7) (d) Tis not a linear transformation

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