Let r(t) = the number of road-runners in year t, and let c(t) the number of coyotes in year t. Then = r(t + 1) = 1.5r(t) — 0.6c(t) c(t + 1) = 0.3r(t) + 0.6c(t) a) If r(0) = 200, and c(0) = 100, then 0. I.e. they both increased by a factor of r(1) = 0 and c(1) = = r(t) = = b) If r(0) = 100, and c(0) = 100, then r(1) = 0. I.e. they both decreased by a factor of r(t) = (Hint: and c(t) = [300] 200 and c(1) = c) If r(0) = 300, and c(0) = 200, then r(t) = and c(t) = = = and c(t) = [100] [200] + 100 100 %. %.
Let r(t) = the number of road-runners in year t, and let c(t) the number of coyotes in year t. Then = r(t + 1) = 1.5r(t) — 0.6c(t) c(t + 1) = 0.3r(t) + 0.6c(t) a) If r(0) = 200, and c(0) = 100, then 0. I.e. they both increased by a factor of r(1) = 0 and c(1) = = r(t) = = b) If r(0) = 100, and c(0) = 100, then r(1) = 0. I.e. they both decreased by a factor of r(t) = (Hint: and c(t) = [300] 200 and c(1) = c) If r(0) = 300, and c(0) = 200, then r(t) = and c(t) = = = and c(t) = [100] [200] + 100 100 %. %.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![Let r(t) = the number of road-runners in year t, and
let c(t)
the number of coyotes in year t.
Then
=
r(t + 1) = 1.5r(t) — 0.6c(t)
c(t + 1) = 0.3r(t) + 0.6c(t)
a) If r(0) = 200, and c(0) = 100, then
0.
I.e. they both increased by a factor of
r(1) = 0 and c(1) =
=
r(t) =
=
b) If r(0) = 100, and c(0) = 100, then
r(1) =
0.
I.e. they both decreased by a factor of
r(t) =
(Hint:
and c(t) =
[300]
200
and c(1) =
c) If r(0) = 300, and c(0) = 200, then
r(t) =
and c(t) =
=
=
and c(t) =
[100] [200]
+
100
100
%.
%.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9978ffa8-8e6a-4550-8363-e044b6a6e895%2F44c6c298-e6c6-4a20-9921-74e821eb3eaf%2F668uey6_processed.png&w=3840&q=75)
Transcribed Image Text:Let r(t) = the number of road-runners in year t, and
let c(t)
the number of coyotes in year t.
Then
=
r(t + 1) = 1.5r(t) — 0.6c(t)
c(t + 1) = 0.3r(t) + 0.6c(t)
a) If r(0) = 200, and c(0) = 100, then
0.
I.e. they both increased by a factor of
r(1) = 0 and c(1) =
=
r(t) =
=
b) If r(0) = 100, and c(0) = 100, then
r(1) =
0.
I.e. they both decreased by a factor of
r(t) =
(Hint:
and c(t) =
[300]
200
and c(1) =
c) If r(0) = 300, and c(0) = 200, then
r(t) =
and c(t) =
=
=
and c(t) =
[100] [200]
+
100
100
%.
%.
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