Let f(x) f-¹(-2) = x + 3 x + 6

Intermediate Algebra
19th Edition
ISBN:9780998625720
Author:Lynn Marecek
Publisher:Lynn Marecek
Chapter10: Exponential And Logarithmic Functions
Section10.1: Finding Composite And Inverse Functions
Problem 64E: Explain how to find the inverse of a function from its equation. Use an example to demonstrate the...
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### Understanding and Finding the Inverse Function

#### Given Function:
Let 
\[ f(x) = \frac{x + 3}{x + 6} \]

To determine \( f^{-1}(-2) \), we first need to find the inverse of the function \( f(x) \).

#### Steps to Find the Inverse:

1. **Express \( y \) in terms of \( x \):**
\[ y = \frac{x + 3}{x + 6} \]

2. **Swap \( x \) and \( y \):**
\[ x = \frac{y + 3}{y + 6} \]

3. **Solve for \( y \) in terms of \( x \):**
\[ x(y + 6) = y + 3 \]
\[ xy + 6x = y + 3 \]
\[ xy - y = 3 - 6x \]
\[ y(x - 1) = 3 - 6x \]
\[ y = \frac{3 - 6x}{x - 1} \]

So, the inverse function \( f^{-1}(x) \) is:
\[ f^{-1}(x) = \frac{3 - 6x}{x - 1} \]

#### Evaluate \( f^{-1}(-2) \):

Substitute \( -2 \) into the inverse function:
\[ f^{-1}(-2) = \frac{3 - 6(-2)}{-2 - 1} \]
\[ f^{-1}(-2) = \frac{3 + 12}{-3} \]
\[ f^{-1}(-2) = \frac{15}{-3} \]
\[ f^{-1}(-2) = -5 \]

Therefore,
\[ f^{-1}(-2) = -5 \]

By working through these steps, we determined that \( f^{-1}(-2) \) equals \(-5\).
Transcribed Image Text:### Understanding and Finding the Inverse Function #### Given Function: Let \[ f(x) = \frac{x + 3}{x + 6} \] To determine \( f^{-1}(-2) \), we first need to find the inverse of the function \( f(x) \). #### Steps to Find the Inverse: 1. **Express \( y \) in terms of \( x \):** \[ y = \frac{x + 3}{x + 6} \] 2. **Swap \( x \) and \( y \):** \[ x = \frac{y + 3}{y + 6} \] 3. **Solve for \( y \) in terms of \( x \):** \[ x(y + 6) = y + 3 \] \[ xy + 6x = y + 3 \] \[ xy - y = 3 - 6x \] \[ y(x - 1) = 3 - 6x \] \[ y = \frac{3 - 6x}{x - 1} \] So, the inverse function \( f^{-1}(x) \) is: \[ f^{-1}(x) = \frac{3 - 6x}{x - 1} \] #### Evaluate \( f^{-1}(-2) \): Substitute \( -2 \) into the inverse function: \[ f^{-1}(-2) = \frac{3 - 6(-2)}{-2 - 1} \] \[ f^{-1}(-2) = \frac{3 + 12}{-3} \] \[ f^{-1}(-2) = \frac{15}{-3} \] \[ f^{-1}(-2) = -5 \] Therefore, \[ f^{-1}(-2) = -5 \] By working through these steps, we determined that \( f^{-1}(-2) \) equals \(-5\).
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