Answer the following using Jacobi Method. Show complete solutions.3. 9x1 + 2x2 - 3x3 = 7 x1 + 12x2 - 9x3 = 2 4x1 -6x2 + 14x3 = 1This is the example that might help.. Step 3. Perform iterction until the values afSystem of Linear Equations (Iterative Methads)Iterative methads ave based on successiveimprovement of initial quesser for the sdlutionITERATIVE METHUDI : JACORI METHODStep 1. Rewrite the systemStep 2. Initializea value for the unknounsof zeru.tep 3. Perform iterction until the values althe unknawn dan't divevge anymore.falutExample:A 3xty-Z =32×+4y+zニフSolution:そtん-e = メY=7-2x-Z4Z:4-xtyスキメーh: x:0; y=0,2=0Ist ItercitionX,こ3-0+O3Y.= 7-2(0) - (0?=1.75Z,?4-04 O42ND ITERAION:メ2ラーy,ナ21-3-175+l>0.7533Y2:1-2x,*2フー2-D.1そz: 4-Xty、 4-1t154-1+1.75=1.1875 Sheuld oo be less than 0.005,5 decimdl3RD ITERATION:メッ=3- y2t2,%3D3-1+1.1875=1.0625%3DYo:フ-2x, -Z27-210.75)-1-1875こ1.0781252,- 4-メetyz 4 - C0-75) +|%3Di,06254'Iteration11.752.0-75|-187531.04251.078125U -994792 0.953125 1.0039061062541.0169271-001628 0-9895830-995985 0.994141 0.9901750.0995371-0006761.00303As required, the difference of the last iteaticn1に2、1:んり1こメ|

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System of Linear Equations (Iterative Methods) Iterative methods ave based on successive Improvement of initial quesses for the sclution ITERCTIVE METHUDI: JACOBI METHOD Step 1. Rewrite the system Step 2. Initialize a value for the unknowns of zeru. tep 3. Perform iterction until the values af the unknown don't diverage anymore. Example: 3xty-z=3 2×t4y tz=フ X-Y+4z= ey Solution: x = 3-y+Z 3 y= 7-2x-Z 4 4-xty Ist Iteration X, = 3-0+O 3 Y.= 7-210)- (0) =175 2,:4-0+O ご 4 2ND ITERAMON: うーy,+ 2,- 3-115 +1 >0.75 3 3 Y2:7-2x,2、:フー2()-1 そz: 4-X,ty、 4-1+1.15 4-1+1.75 =1.1875 %3D

System of Linear Equations (Iterative Methods) Iterative methods ave based on successive Improvement of initial quesses for the sclution ITERCTIVE METHUDI: JACOBI METHOD Step 1. Rewrite the system Step 2. Initialize a value for the unknowns of zeru. tep 3. Perform iterction until the values af the unknown don't diverage anymore. Example: 3xty-z=3 2×t4y tz=フ X-Y+4z= ey Solution: x = 3-y+Z 3 y= 7-2x-Z 4 4-xty Ist Iteration X, = 3-0+O 3 Y.= 7-210)- (0) =175 2,:4-0+O ご 4 2ND ITERAMON: うーy,+ 2,- 3-115 +1 >0.75 3 3 Y2:7-2x,2、:フー2()-1 そz: 4-X,ty、 4-1+1.15 4-1+1.75 =1.1875 %3D

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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