X 8.9. Let A = 3 -2 x² value(s) of x for which A is singular. Compute det(A). Use det(A) to determine the

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**Matrix and Determinant**

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**Example:**
Let \( A = \begin{bmatrix} x - 3 & \frac{x}{x^2} \\ -2 & x^2 \end{bmatrix} \). Compute det(A). Use det(A) to determine the value(s) of \( x \) for which \( A \) is singular.

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In this example, the task is to find the determinant of matrix \( A \) and use it to determine for what values of \( x \), matrix \( A \) is singular. A matrix is singular if its determinant is zero.

To compute the determinant of a 2x2 matrix \( \begin{bmatrix}a & b \\ c & d \end{bmatrix} \), use the formula:

\[ \text{det}(A) = ad - bc \]

In this case, matrix \( A \) is given by:

\[ A = \begin{bmatrix} x - 3 & \frac{x}{x^2} \\ -2 & x^2 \end{bmatrix} \]

So, applying the determinant formula:

\[ \text{det}(A) = (x - 3) \cdot (x^2) - \left( \frac{x}{x^2} \cdot (-2) \right) \]

Simplify the determinant equation and solve for \( x \) to find the values that make \( A \) singular.
Transcribed Image Text:**Matrix and Determinant** --- **Example:** Let \( A = \begin{bmatrix} x - 3 & \frac{x}{x^2} \\ -2 & x^2 \end{bmatrix} \). Compute det(A). Use det(A) to determine the value(s) of \( x \) for which \( A \) is singular. --- In this example, the task is to find the determinant of matrix \( A \) and use it to determine for what values of \( x \), matrix \( A \) is singular. A matrix is singular if its determinant is zero. To compute the determinant of a 2x2 matrix \( \begin{bmatrix}a & b \\ c & d \end{bmatrix} \), use the formula: \[ \text{det}(A) = ad - bc \] In this case, matrix \( A \) is given by: \[ A = \begin{bmatrix} x - 3 & \frac{x}{x^2} \\ -2 & x^2 \end{bmatrix} \] So, applying the determinant formula: \[ \text{det}(A) = (x - 3) \cdot (x^2) - \left( \frac{x}{x^2} \cdot (-2) \right) \] Simplify the determinant equation and solve for \( x \) to find the values that make \( A \) singular.
#### Determinants of Matrices

In this section, we will explore how to determine if a matrix is singular based on its determinant.

Consider the determinant expressed as follows:

\[ \text{det}(A) = x^3 - 3x^2 + 2x \]

This determinant is singular if the determinant function equals zero. In this case, the function \( x^3 - 3x^2 + 2x \) equals zero when \( x \) takes specific values.

#### Finding Singular Values

To determine the values of \( x \) that will make the matrix singular, we set the determinant to zero and solve for \( x \):

\[ x^3 - 3x^2 + 2x = 0 \]

Factoring the polynomial, we get:

\[ x(x^2 - 3x + 2) = 0 \]
\[ x(x - 1)(x - 2) = 0 \]

This equation will be satisfied if \( x \) equals:

\[ x = 0 \]
\[ x = 1 \]
\[ x = 2 \]

Therefore, the given matrix is singular when \( x = 0 \), \( x = 1 \), or \( x = 2 \).
Transcribed Image Text:#### Determinants of Matrices In this section, we will explore how to determine if a matrix is singular based on its determinant. Consider the determinant expressed as follows: \[ \text{det}(A) = x^3 - 3x^2 + 2x \] This determinant is singular if the determinant function equals zero. In this case, the function \( x^3 - 3x^2 + 2x \) equals zero when \( x \) takes specific values. #### Finding Singular Values To determine the values of \( x \) that will make the matrix singular, we set the determinant to zero and solve for \( x \): \[ x^3 - 3x^2 + 2x = 0 \] Factoring the polynomial, we get: \[ x(x^2 - 3x + 2) = 0 \] \[ x(x - 1)(x - 2) = 0 \] This equation will be satisfied if \( x \) equals: \[ x = 0 \] \[ x = 1 \] \[ x = 2 \] Therefore, the given matrix is singular when \( x = 0 \), \( x = 1 \), or \( x = 2 \).
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