sure to answer all parts. nicrobiologist is preparing a medium on which to culture E. coli bacteria. She buffers the med € 7.00 to minimize the effect of acid-producing fermentation. What volumes of equimolar aque utions of K₂HPO4 and KH₂PO4 must she combine to make 450.0 mL of the pH 7.00 buffer? values for phosphoric acid: = 7.2 × 10-³
sure to answer all parts. nicrobiologist is preparing a medium on which to culture E. coli bacteria. She buffers the med € 7.00 to minimize the effect of acid-producing fermentation. What volumes of equimolar aque utions of K₂HPO4 and KH₂PO4 must she combine to make 450.0 mL of the pH 7.00 buffer? values for phosphoric acid: = 7.2 × 10-³
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Be sure to answer all parts.
A microbiologist is preparing a medium on which to culture E. coli bacteria. She buffers the medium at
pH 7.00 to minimize the effect of acid-producing fermentation. What volumes of equimolar aqueous
solutions of K₂HPO4 and KH₂PO4 must she combine to make 450.0 mL of the pH 7.00 buffer?
Ka values for phosphoric acid:
Kal = 7.2 × 10-3
Ka2= 6.3 × 10-8
Ka3 = 4.2 × 10-13
Volume H₂PO4 =
Volume HPO42
=
mL
mL](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F74306ebc-930f-47cd-8784-93dfead9c2ca%2F70fc89c1-4dac-4bf3-920b-168918f6cc35%2Fcloltfj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Be sure to answer all parts.
A microbiologist is preparing a medium on which to culture E. coli bacteria. She buffers the medium at
pH 7.00 to minimize the effect of acid-producing fermentation. What volumes of equimolar aqueous
solutions of K₂HPO4 and KH₂PO4 must she combine to make 450.0 mL of the pH 7.00 buffer?
Ka values for phosphoric acid:
Kal = 7.2 × 10-3
Ka2= 6.3 × 10-8
Ka3 = 4.2 × 10-13
Volume H₂PO4 =
Volume HPO42
=
mL
mL
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