Suppose you performed a similar experiment using an unknown carbonate sample. The pressure and volume were measured after the temperature stabilized at 21.5 °C. Given the data in the table, calculate the moles of CO₂ produced. initial pressure (atm) initial gas volume (mL) volume of 1.0 M HCI solution added to fully consume the carbonate sample (ml) moles of CO₂: 18.33 PV=nRT Incorrect final pressure (atm) final gas volume (mL) What is the stoichiometric ratio between HCI and CO₂? n=PV/RT=1.32*0.022/0.0821*294.5-0.0012moles stoichiometric ratio between HCI and CO2=0.022/0.0012-18.33 1.000 240.0 22.0 2.320 218.0 mol

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Suppose you performed a similar experiment using an unknown carbonate sample. The pressure and volume were measured after the temperature stabilized at 21.5°C. Given the data in the table, calculate the moles of CO₂ produced.

| Measurement                                      | Value          |
|--------------------------------------------------|----------------|
| Initial pressure (atm)                           | 1.000          |
| Initial gas volume (mL)                          | 240.0          |
| Volume of 1.0 M HCl solution added (mL)          | 22.0           |
| Final pressure (atm)                             | 2.320          |
| Final gas volume (mL)                            | 218.0          |

**Moles of CO₂:**

The initial attempt to calculate the moles of CO₂ resulted in "18.33 mol," which is incorrect.

**Calculating the Stoichiometric Ratio:**

What is the stoichiometric ratio between HCl and CO₂?

Using the ideal gas law:
\[ PV = nRT \]

Given:
- \( P = 1.32 \, \text{atm} \)
- \( V = 0.022 \, \text{L (converted from 22.0 mL)} \)
- \( R = 0.0821 \, \left(\text{L atm/mol K}\right) \)
- \( T = 294.5 \, \text{K} \, (21.5 + 273) \)

The calculation:
\[ n = \frac{PV}{RT} = \frac{1.32 \times 0.022}{0.0821 \times 294.5} = 0.0012 \, \text{moles} \]

The stoichiometric ratio between HCl and CO₂ is:
\[ = \frac{0.022}{0.0012} = 18.33 \]
Transcribed Image Text:Suppose you performed a similar experiment using an unknown carbonate sample. The pressure and volume were measured after the temperature stabilized at 21.5°C. Given the data in the table, calculate the moles of CO₂ produced. | Measurement | Value | |--------------------------------------------------|----------------| | Initial pressure (atm) | 1.000 | | Initial gas volume (mL) | 240.0 | | Volume of 1.0 M HCl solution added (mL) | 22.0 | | Final pressure (atm) | 2.320 | | Final gas volume (mL) | 218.0 | **Moles of CO₂:** The initial attempt to calculate the moles of CO₂ resulted in "18.33 mol," which is incorrect. **Calculating the Stoichiometric Ratio:** What is the stoichiometric ratio between HCl and CO₂? Using the ideal gas law: \[ PV = nRT \] Given: - \( P = 1.32 \, \text{atm} \) - \( V = 0.022 \, \text{L (converted from 22.0 mL)} \) - \( R = 0.0821 \, \left(\text{L atm/mol K}\right) \) - \( T = 294.5 \, \text{K} \, (21.5 + 273) \) The calculation: \[ n = \frac{PV}{RT} = \frac{1.32 \times 0.022}{0.0821 \times 294.5} = 0.0012 \, \text{moles} \] The stoichiometric ratio between HCl and CO₂ is: \[ = \frac{0.022}{0.0012} = 18.33 \]
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