In your first task, you are required to prepare a 100 mL solution of sodium bicarbonate at a concentration of 0.50 M. Complete the following table and calculate the mass of sodium bicarbonate needed to prepare this solution. Molecular weight of sodium bicarbonate Required final concentration Required final volume Amount of sodium bicarbonate needed to make 1 L at 0.5 M Amount of sodium bicarbonate needed to make 100 mL at 0.5 M Mass (g) = Amount (mol) × Molecular Weight (g/mol) Value 84.01 Now that you know the amount of sodium bicarbonate in mol needed to make your solution, you can convert this value into the mass by using the molecular weight of the compound. The following equation may be helpful: Mass of sodium bicarbonate needed to make 100 mL at 0.5 M Units g/mol M (mol/L) L mol mol In the 100 mL 0.5 M solution, how many molecules of sodium bicarbonate have been added. Hint - In 1 mole there are 6.022 × 1023 molecules.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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In your first task, you are required to prepare a 100 mL solution of sodium bicarbonate at a
concentration of 0.50 M. Complete the following table and calculate the mass of sodium
bicarbonate needed to prepare this solution.
Molecular weight of sodium bicarbonate
Required final concentration
Required final volume
Amount of sodium bicarbonate needed to make 1 L at 0.5 M
Amount of sodium bicarbonate needed to make 100 mL at 0.5 M
Mass (g) = Amount (mol) × Molecular Weight (g/mol)
Value
84.01
Now that you know the amount of sodium bicarbonate in mol needed to make your solution, you
can convert this value into the mass by using the molecular weight of the compound. The following
equation may be helpful:
Mass of sodium bicarbonate needed to make 100 mL at 0.5 M
Units
g/mol
M (mol/L)
L
mol
mol
g
In the 100 mL 0.5 M solution, how many molecules of sodium bicarbonate have been added. Hint - In
1 mole there are 6.022 × 10²³ molecules.
Transcribed Image Text:In your first task, you are required to prepare a 100 mL solution of sodium bicarbonate at a concentration of 0.50 M. Complete the following table and calculate the mass of sodium bicarbonate needed to prepare this solution. Molecular weight of sodium bicarbonate Required final concentration Required final volume Amount of sodium bicarbonate needed to make 1 L at 0.5 M Amount of sodium bicarbonate needed to make 100 mL at 0.5 M Mass (g) = Amount (mol) × Molecular Weight (g/mol) Value 84.01 Now that you know the amount of sodium bicarbonate in mol needed to make your solution, you can convert this value into the mass by using the molecular weight of the compound. The following equation may be helpful: Mass of sodium bicarbonate needed to make 100 mL at 0.5 M Units g/mol M (mol/L) L mol mol g In the 100 mL 0.5 M solution, how many molecules of sodium bicarbonate have been added. Hint - In 1 mole there are 6.022 × 10²³ molecules.
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