Suppose you have run k-means using k=2 and k=5. You find that the cost function J is much higher for k=5 than k=2. What can you conclude? O a. In the run with k=5, k-means got stuck in a bad local minimum. You should try re-running k-means with multiple random initializations. O b. The ideal number of clusters is k=2. O c. In the run with k=2, k-means got lucky. You should try re-running k-means with k=2 and different random initializations until it performs no better than with k=5. O d. This is mathematically impossible. There must be a bug in the code.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Suppose you have run k-means using k=2 and k=5. You find that the cost function J is
much higher for k=5 than k=2. What can you conclude?
a. In the run with k=5, k-means got stuck in a bad local minimum. You should try
re-running k-means with multiple random initializations.
O b. The ideal number of clusters is k=2.
O c. In the run with k=2, k-means got lucky. You should try re-running k-means with k=2
and different random initializations until it performs no better than with k=5.
O d. This is mathematically impossible. There must be a bug in the code.
Transcribed Image Text:Suppose you have run k-means using k=2 and k=5. You find that the cost function J is much higher for k=5 than k=2. What can you conclude? a. In the run with k=5, k-means got stuck in a bad local minimum. You should try re-running k-means with multiple random initializations. O b. The ideal number of clusters is k=2. O c. In the run with k=2, k-means got lucky. You should try re-running k-means with k=2 and different random initializations until it performs no better than with k=5. O d. This is mathematically impossible. There must be a bug in the code.
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