Suppose you have an experiment set up in which a laser enters a glass of water from below at the critical angle and reflects off the water-air interface with total internal reflection. a) What is the critical angle for a water-air interface? b) Now someone pours a thick layer of oil on top of the water in your experiment. What happens? Will the laser beam still be at the critical angle? If not, what will the new critical angle be at the oil-water interface (if any)? n for water = 1.333 n for oil = 1.2 n for air = 1.0

icon
Related questions
Question

Suppose you have an experiment set up in which a laser enters a glass of water from below at the critical angle and reflects off the water-air interface with total internal reflection.

a) What is the critical angle for a water-air interface?

b) Now someone pours a thick layer of oil on top of the water in your experiment. What happens? Will the laser beam still be at the critical angle? If not, what will the new critical angle be at the oil-water interface (if any)?

n for water = 1.333

n for oil = 1.2

n for air = 1.0

Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 3 images

Blurred answer