9. a) Find the angle of incidence 9 at the water-oil interface such that the condition for total internal reflection (at the oil-air boundary) is exactly satisfied. b) If 9 is decreased, is the reflection at the oil-air interface still total? c) What if 9 is increased? d) If the oil were not present, how would the answer in part (b) change? Note: noil =1.48, nwater =1.33. Air Oil Water
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- State the approximate value of the critical angle for (a) glass- air surface (b) water- air surface.. a. A ray of light enters a fiber optic cable with index of refraction n from air at an angle as shown below. Let the angle 0 be 69°. For total internal reflection to occur at the cable- air interface, what must be the value of n? n=1.3 nair = 1 Bd OR 8 n Think & Prepare You have three unkowns in this problem, the angle of refraction R, the angle of refraction and n. 1. Set-up Snell's Law equation relating 6, R, and n. 2. Set-up the critical angle relationship between cand n 3.0+0=? sine 4. You may need some trigonometric identities such as sin (90° - 0) = ? and = 2. cose b. In the problem above, the angle e increases. How does this affect what n must be to ensure total internal reflection? A) n will decrease because the critical angle will become larger B) n will decrease becuase the equation for the critical angle is proportional to 1/n of the material C) n will increase because the critical angle will become smaller D) n will increase becuase the equation for the critical angle is…1) A light ray incoming from air hits a glass surface. Incident angle and refraction angle is calculated at the table below. a)Find the index of refraction of the medium for 3 different angles Incoming Refracted index N/A 30 8.7 45 12.2 60 15.3 b) Plot sin(theta1) vs sin(theta2) and obtain best fit line. What does the numeric value of the slope corresponds to in Snell's Law equation.
- Consider a fiber like the one sketched below. Take the index of refraction of the core to be n₁ = 1.52 and the index of refraction of the cladding to be n₂ = 1.46. A) What is the critical angle for the core/cladding interface? B) If the input angle from air is 00= 10° Calculate 01. C) If the input angle from air is 80-10° Calculate y. D) If the input angle from air is 00=10° will the ray be guided by the fiber with low loss? E) If the input angle from air is 00=30° Calculate 0₁. F) If the input angle from air is 00=30° Calculate y. G) If the input angle from air is 00=30° will the ray be guided by the fiber with low loss? H) What is the maximum input angle from air for a ray that will be guided with low loss by this fiber?Needs Complete typed solution with 100 % accuracy.For the optical fiber shown in the figure, find the minimum angle of incidence (0;) that will result in total internal reflection if the refractive index for the cladding (n2) is 1.46 and the refractive index of the core is (A.) n1 = 1.51 and (B.) nị = 1.76. Cone of acceptance п, Core Cladding (n,) А. B.
- ou can determine the index of refraction of a substance by determining its critical angle. (a) What is the index of refraction of a substance that has a critical angle of 58.9° when submerged in ethanol, which has an index of refraction of 1.361?(b) What would the critical angle be for this substance in air? °Optical fibers are a central part of technology for rapid information transmission with a high level of efficiency. A new type of optical fiber is crafted with an index of refraction n = less than that of water in the vicinity of room temperature, where NH2O fact that n < nH20 potentially problematic if the fiber should be submerged? 1.25 = 1.33. Why is the O A. Total internal reflection would be frustrated, allowing loss of signal. O B. Internal reflection would actually be enhanced, so there is no problem. C. Electric eels might have free internet access.What is the critical angle for total internal reflection for glass in air? Assume that nglass= 1.50 and nair = 1.00.
- 1) Light is incident from benzene on an interface with ice. If the angle ofincidence in the benzene is 42.00°, calculate the angle of refraction in ice. 2) Is total internal reflection possible at this interface if the light is incidentthrough benzene? If the answer is yes, calculate the critical angle and report theangle as measured in degrees. If no, simply enter “-1” (exactly, without thequotes) to indicate that the critical angle does not exist. 3) Light is incident from one medium on an interface with a piece of salt (sodiumchloride). If the angle of incidence in the first medium is 69°, and the lightrefracts in the salt at an angle of 55.379°, what is the identity of the incidentmedium? A) sodium chloride B) carbon tetrachloride C) hydrogen gas D) fresh water E) zircon F) benzene G) air H) polystyrene I) ethanol J) vacuum 4) Is total internal reflection possible at this interface if the light is incident through the mystery material? If the answer is yes, calculate the critical…Building contractors often install double-glazed windows to prevent thermal energy (heat) from entering or exiting a building. In addition to being effective insulators, such windows present interesting optical effects. 62.0 mm In the figure, a double-glazed window consists of two identical of glass (ng panes 1.54), each yg thick, separated by an air gap of ya = 49.6 mm. Use na = 1.00 for the index of refraction of air. = If light incident on the glass makes an angle of = 40.00° with respect to the glass, find the shift in path Ax as the light enters the room. Ax = 42.36 Incorrect glass air glass mm