Consider a fiber like the one sketched below. Take the index of refraction of the core to be n₁ = 1.52 and the index of refraction of the cladding to be n₂=1.46. A) What is the critical angle for the core/cladding interface? B) If the input angle from air is 00=10° Calculate 01. C) If the input angle from air is 00=10° Calculate .
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- as shown in image, light from a vacuum is incident on a shard of shawtonium. backside of the shard is up against an unknown material. when light strikes the backside, total internal reflection occurs. the light then enmerges from the side of the shard and resumes traveling through a vacuum. index of refraction of shawtonium is 2. determine theta 1 and 2.Assume that a material is composed of 3 layers in descending order: air (nair = 1.00), water (nwater = 1.33), and glass (nglass= 1.52). Then, assume that a monochromatic light ray in the air passes through the surface of water with an angle of incidence 0₁ = 40 degrees. A. Find the angle of refraction in glass after it passes completely through the water layer. B. Find how fast is the light ray moving in the glass?Asap plzzz
- A ray of light passes through a prism, making the minimum angle of deviation. The rays enter and emerge at 7° from the normal to the surface. What is the index of refraction of the material, if the prism angle is 50°?Part of your refraction experiment is on performing a total internal reflection. You measure the critical angle for some oil as 40o. Therefore the refractive index of that oil should be Group of answer choices 2.02 1.56Assume that a material is composed of 3 layers in descending order: air (nair = 1.00), water (nwater = 1.33), and glass (nglass= 1.52). Then, assume that a monochromatic light ray in the air passes through the surface of water with an angle of incidence 0₁ = 40 degrees. A. Find the angle of refraction in glass after it passes completely through the water layer. B. Find how fast is the light ray moving in the glass?
- An endoscope silica fibre efficiently contains all central light rays that subtend an angle greater than 0, = 42.00° as measured relative to the normal of the side surface of a silica-based fibre (labelled as 0, in the following diagram). What is the refractive index of the fibre? Take the optical fibre to be a solid cylinder residing in air. The following diagram shows a central light ray. The ray passes through the axis of symmetry of the optical fibre. O1.35 1.49 1.46 1.53 0.74 1.47A laser and a set of five mirrors are arranged to create a perfect hexagon of laser light. What is the incident angle of the light when it hits the mirrors? (The internal angle of a hexagon is 120 degrees).What is the critical angle for total internal reflection for glass in air? Assume that nglass= 1.50 and nair = 1.00.
- Suppose you have an unknown clear substance immersed in water, and you wish to identify it by finding its index of refraction. You arrange to have a beam of light enter it at an angle of 45.0° with respect to the normal, and you observe the angle of refraction to be 40.3°. A. What is the index of refraction of the substance? B. What is its likely identity?Calculate the angle of refraction at the air/core interface, r . critical angle, c and incident angle at the core/cladding interface, i . Will this light ray propagate down the fiber? You have the following data: nair = 1, ncore = 1.46, ncladding =1.43, incident =12o Answers: r = 8.2o , c = 78.4o , i = 81.8o light will propagate Formula summery Index of Refraction n= n sin 01= n, sin 0, o = sin1(2) Snell's Law Critical Angle Acceptance angle a= sin1 Numerical Aperture NA = sin a = ni- nị