Module 6Hypothesis TestingNameCourse and YearExercise 6.1,1. Suppose you are testing Ho = .45 versus Ha >.45 random sample of 310 peopleproduces a value of p = .465. Use= .05 to test this hypothesis.2. Instructions: Five - step Hypothesis Testing Procedure Used:A criminologist was interested whether there was disparity in sentencing based onthe race of the defendant. She selected at random 18 burglary convictions andcompared the prison terms given to the 10 whites and 8 blacks sampled. Thesentenced length s (in years) are shown for the white and blacks offenders. Using thedata, test the null hypothesis that white and blacks convicted burglary in thisjurisdiction do not differ with respect prison sentence length.Black8735 43547 5 5 6 4 3 2454WhiteNote: Follow all the steps and use two decimal places, round off if possible.Analysis of Variance (ANOVA)Exercise 6.2.1. Compute a one - way ANOVA on the following data. Use .05 level of significance3133413.6.351Determine the observed F value. Compare the observed F value with the criticaltable F value and decide whether to reject the null hypothesis.Note: Use other long bond paper.

Hypothesis testing is an inference process to draw the conclusions about the population parameter.…

Answered: Suppose you are testing Ho =.45 versus…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

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The recidivism rate for convicted sex offenders is 13%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 309 convicted sex offenders who were also drug addicts, 31 of them became repeat offenders. What can be concluded at the a = 0.01 level of significance? For this study, we should use Select an answer The null and alternative hypotheses would be: Ho: ? ✓ Select an answer H₁: ? Select an answer (please enter a decimal) (Please enter a decimal) The test statistic ? ✓ = The p-value = The p-value is ? va Based on this, we should [Select an answer the null hypothesis. Thus, the final conclusion is that ... (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) O The data suggest the population proportion is not significantly different from 13% at a = 0.01, so there is statistically insignificant evidence to conclude that the population proportion of convicted sex offender drug addicts who become…
The population of healthy female adults, the mean red blood cell count (RBC) is 4.8 (millions of cells per cubic millimeter of whole blood). A researcher thinks the RBC is underestimated, so she conducts a test of significance using Null Hypothesis: µ ≤ 4.8 vs. Alternative Hypothesis: µ >4.8. If the true mean RBC is 4.75 and the null hypothesis is rejected, out of the four options below, what has occured? Type 1 Error, Type 2 Error, No error, OR can’t tell without knowing the degrees of freedom?
An insurance company is interested in studying the mean hospitalization time of patients who suffer strokes at a certain hospital. The hospital claims the mean length of stay is 22 days, but the insurance company believes it is less than claimed. A random sample of 9 patients showed a sample mean stay of 18 days with a sample standard deviation of 3 days. They would like to conduct the test using alpha = 0.1. %3D Calculate the test statistic for the test and enter your answer in the first blank. Round your answer to two decimals. Enter the critical value cutoff point for the rejection region in the second blank. Blank # 1 Blank # 2 Next Page Page 8 of 15 126 NOV 18 MacBook Pro
The recidivism rate for convicted sex offenders is 11%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 337 convicted sex offenders who were also drug addicts, 30 of them became repeat offenders. What can be concluded at the a = 0.10 level of significance? For this study, we should use Select an answer The null and alternative hypotheses would be: Ho: ? ✓ Select an answer H₁: ? ✓ Select an answer (please enter a decimal) (Please enter a decimal) The test statistic ? ✓ = The p-value = The p-value is? ♥ α Based on this, we should [Select an answer the null hypothesis. Thus, the final conclusion is that ... (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) O The data suggest the population proportion is not significantly different from 11% at a = 0.10, so there is statistically insignificant evidence to conclude that the population proportion of convicted sex offender drug addicts who become…
I randomly sample 219 students and ask them to provide their USF GPA. I wish to determine if the average GPA of all USF students ex mu + 3.25 ceeds 3.25. Unfortunately, I generated the printout shown here: One-Sample T Test Null Hypothesis: H - 3.25 Alternative Hyp: u- 3.25 Variable Mean SE DF GPA 3.3121 0.0340 1.82 218 0.0694 Cases Included 219 What assumption is needed for this analysis to be valid? None. The Central Limit Theorem applies and no other assumptions are needed. The GPAS of all USF students need to be approximately normally distributed The mean GPA of all USF students need to be approximately normally distributed
The effectiveness of surgery for weight loss reported here found that "The surgery was associated with significantly greater weight loss [than the control group who dieted] through 2 years (61.3 versus 11.2 pounds, P<0.001)." What test could have been used and how would it have been computed?
The Wilcoxon signed-rank test can be used to perform a hypothesis test for a population median, η, as well as for a population mean, µ. Why is that so?
Which combination would lead you to Fail to Reject H0? ANOVA: Fobt = 3.61 Fcrit = 2.55 2-tailed t-test: tobt = 2.36 tcrit = 1.89 Correlation: robt = 0.68 rcrit = 0.64 Chi-Square GOF: χ2obt = 3.24 χ2crit = 4.25
A repeated-measures ANOVA was calculated with df = 1, 14. If the same data were analyzed with a repeated-measures t test, how many degrees of freedom would be used with the t statistic?
Question 7 > You wish to test the following claim (Ha) at a significance level of a = 0.05. H.: 41 Ha: µ1 7 42 You believe both populations are normally distributed, but you do not know the standard deviations for either. However, you have reason to believe that the variances of the two populations are equal. You obtain a sample of size nį = 14 with a mean of M1 first population. You obtain a sample of size n2 of SD2 = 7.4 from the second population. = 67.8 and a standard deviation of SD1 19 with a mean of M2 15.5 from the 61.7 and a standard deviation In the answer box below insert 2.0395 as the critical value for this test. (Report answer accurate to three decimal places.) critical value What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = %3D The test statistic is... O in the critical region O not in the critical region
IID Suppose X1, ..., X, N(u, o?). Construct a 95% confidence interval for o? when u is known.

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Suppose you are testing Ho =.45 versus Ha > .45 random sample of 310 people produces a value of p= .465. Use= .05 to test this hypothesis. %3D Instruot