Use the AustStates data. Perform a repeated measures ANOVA using the 9 years as the paired variables and the states as the observations. Based on the Greenhouse-Geisser p-value of p=0.130, sphericity can be assumed for these data. The result of the analysis is F=9.563 on degrees of freedom, for a p-value of You the null hypothesis. 8 and 56, p<0.001, reject 8 and 56, p<0.001, fail to reject O 1.0 and 7.3, p=0.016, reject O 1.0 and 7.3, p=0.016, fail to reject

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Chapter1: Starting With Matlab
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Question
A
В
D
E
F
G
H
1 state
pop1917
pop1927
рop1937
pop1947
рop1957
pop1967
рop1977
рop1987
pop1997
2 NSW
1904
2402
2693
2985
3625
4295
5002
5617
6274
3 Vic
1409
1727
1853
2055
2656
3274
3837
4210
4605
4 Qld
683
873
993
1106
1413
1700
2130
2675
3401
5 SA
440
565
589
646
873
1110
1286
1393
1480
6 WA
306
392
457
502
688
879
1204
1496
1798
7 Tas
193
211
233
257
326
375
415
449
474
8
NT
5
4
6
11
21
62
104
158
187
9 АСT
8
11
17
38
103
214
265
310
10
Transcribed Image Text:A В D E F G H 1 state pop1917 pop1927 рop1937 pop1947 рop1957 pop1967 рop1977 рop1987 pop1997 2 NSW 1904 2402 2693 2985 3625 4295 5002 5617 6274 3 Vic 1409 1727 1853 2055 2656 3274 3837 4210 4605 4 Qld 683 873 993 1106 1413 1700 2130 2675 3401 5 SA 440 565 589 646 873 1110 1286 1393 1480 6 WA 306 392 457 502 688 879 1204 1496 1798 7 Tas 193 211 233 257 326 375 415 449 474 8 NT 5 4 6 11 21 62 104 158 187 9 АСT 8 11 17 38 103 214 265 310 10
Use the AustStates data. Perform a repeated measures ANOVA using the
9 years as the paired variables and the states as the observations. Based
on the Greenhouse-Geisser p-value of p=0.130, sphericity can be
assumed for these data. The result of the analysis is F=9.563 on
degrees of freedom, for a p-value of
You
the null
hypothesis.
8 and 56, p<0.001, reject
8 and 56, p<0.001, fail to reject
1.0 and 7.3, p=0.016, reject
1.0 and 7.3, p=0.016, fail to reject
Transcribed Image Text:Use the AustStates data. Perform a repeated measures ANOVA using the 9 years as the paired variables and the states as the observations. Based on the Greenhouse-Geisser p-value of p=0.130, sphericity can be assumed for these data. The result of the analysis is F=9.563 on degrees of freedom, for a p-value of You the null hypothesis. 8 and 56, p<0.001, reject 8 and 56, p<0.001, fail to reject 1.0 and 7.3, p=0.016, reject 1.0 and 7.3, p=0.016, fail to reject
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