Suppose you are interested in studying whether scent affects spatial reasoning abilities. You decide to test spatial reasoning using completion time scores for the paper-folding test with five people, repeating the test on each person with three different scents (cinnamon, lavender, and peppermint). In this experiment, the null hypothesis is that: O There are no differences in the mean completion times among the scents compared O There are no individual differences in the completion time means O The completion time mean for at least one scent is different from another The factor of interest is the , and the dependent variable is the The results of the study are presented in the following data table. All scores are times necessary to complete the paper-folding task, recorded in seconds. Scent Participant Cinnamon Lavender Peppermint Participant Totals 3.41 3.40 3.49 P = 10.30 = 3.29 3.47 3.25 P = 10.01 3 %3D 3.70 3.71 3.63 P = 11.04 15 D 3.68 4.08 3.88 P = 11.64 G 54.70 3.80 4.17 3.74 P = 11.71 ΣΧ2 200.4864 T = 17.88 T = 18.83 T 17.99 SS = 0.1858 SS = 0.4866 SS = 0.2335 The three treatments in the experiment define three populations of interest. You use an ANOVA to test the hypothesis that the three population means are equal. Present the results of your analysis in the following ANOVA table by entering the missing df values and selecting the correct values for the missing SS, MS, and F entries. (Note: For best results, retain at least two additional decimal points throughout your calculations. Depending on the order in which you do these calculations and the number of digits you retain, you may find slight rounding differences in the last digit between your answers and the answer choices.) ANOVA Table df MS F Source Between treatments 0.0755 Within treatments 0.1973 Between subjects Error 14 Total
Suppose you are interested in studying whether scent affects spatial reasoning abilities. You decide to test spatial reasoning using completion time scores for the paper-folding test with five people, repeating the test on each person with three different scents (cinnamon, lavender, and peppermint). In this experiment, the null hypothesis is that: O There are no differences in the mean completion times among the scents compared O There are no individual differences in the completion time means O The completion time mean for at least one scent is different from another The factor of interest is the , and the dependent variable is the The results of the study are presented in the following data table. All scores are times necessary to complete the paper-folding task, recorded in seconds. Scent Participant Cinnamon Lavender Peppermint Participant Totals 3.41 3.40 3.49 P = 10.30 = 3.29 3.47 3.25 P = 10.01 3 %3D 3.70 3.71 3.63 P = 11.04 15 D 3.68 4.08 3.88 P = 11.64 G 54.70 3.80 4.17 3.74 P = 11.71 ΣΧ2 200.4864 T = 17.88 T = 18.83 T 17.99 SS = 0.1858 SS = 0.4866 SS = 0.2335 The three treatments in the experiment define three populations of interest. You use an ANOVA to test the hypothesis that the three population means are equal. Present the results of your analysis in the following ANOVA table by entering the missing df values and selecting the correct values for the missing SS, MS, and F entries. (Note: For best results, retain at least two additional decimal points throughout your calculations. Depending on the order in which you do these calculations and the number of digits you retain, you may find slight rounding differences in the last digit between your answers and the answer choices.) ANOVA Table df MS F Source Between treatments 0.0755 Within treatments 0.1973 Between subjects Error 14 Total
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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