Suppose x is a normally distributed random variable with mean of 5 and a variance of 4. The probability that x is greater than 10.52 is? The correct answer is .0029
Suppose x is a normally distributed random variable with mean of 5 and a variance of 4. The probability that x is greater than 10.52 is? The correct answer is .0029
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Suppose x is a
The correct answer is .0029
How do I calculate this on a calculator? I understand 10.52 - 5/2. I do not understand where the rest of the numbers come from to get to the calculation. P(z what values are being used? Is it from a table?
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