5. Is it better to fish from the shore or a boat? Let x be a random variable representing the number of hours taken to catch a fish. The table below contains the data taken over several months for B from the shore, and A from a boat. Oct Nov Dec Jan Feb Mar Apr B (shore) A (boat) 1.6 1.8 2.0 3.2 3.9 3.6 3.3 1.5 1.4 1.6 2.2 3.3 3.0 3.8 Use a 1% level of significance to determine if there is a difference in the population mean hours per fish using a boat compared with fishing from shore. (This is a paired difference problem.)

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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#5 It must be in the format of the second picture.

**Sample and Population Analysis for Statistical Testing**

**Random Variable:** \(\bar{X}\)

**Special Considerations/Characteristics:**  
(Blank)

**Given:**  
\[ P\left(\bar{X} \leq 6820\right) = 0.0030 \]

**Question:**  
(Blank)

**Sample Information:**

- \( n = 50 \)
- \(\bar{x} = 6820\)

**Population Information:**

- \(\mu = 7500\)  
- \(\sigma = 1750\)

**Sampling Distribution:**

**Type:** Normal

**Why Justified:** Central Limit Theorem (CLT), as \(n > 30\)

**Test Statistic:** \(Z\)

**Calculations:**

1. **Mean of Sampling Distribution:**
   \[ \mu_{\bar{X}} = \mu = 7500 \]

2. **Standard Error:**
   \[ \sigma_{\bar{X}} = \frac{\sigma}{\sqrt{n}} = \frac{1750}{\sqrt{50}} \approx 247.4874 \]

3. **Test Statistic Value:**
   \[ Z = \frac{\bar{X} - \mu_{\bar{X}}}{\sigma_{\bar{X}}} = \frac{6820 - 7500}{247.4874} = -2.75 \]

**Diagram Explanation:**

There is a bell curve representing a normal distribution, centered at the population mean, 7500. The area to the left of the point \(-2.75\) is shaded, indicating the probability \(P(Z \leq -2.75) = 0.0030\). This area corresponds to the lower tail of the distribution, which is significant at this level.

**Conclusion:**

The probability that the sample mean \(\bar{X}\) is less than or equal to 6820 is very small (0.3%), suggesting that such an observation is unusual if the true population mean is indeed 7500. This outcome may be considered statistically significant depending on the chosen threshold for significance.
Transcribed Image Text:**Sample and Population Analysis for Statistical Testing** **Random Variable:** \(\bar{X}\) **Special Considerations/Characteristics:** (Blank) **Given:** \[ P\left(\bar{X} \leq 6820\right) = 0.0030 \] **Question:** (Blank) **Sample Information:** - \( n = 50 \) - \(\bar{x} = 6820\) **Population Information:** - \(\mu = 7500\) - \(\sigma = 1750\) **Sampling Distribution:** **Type:** Normal **Why Justified:** Central Limit Theorem (CLT), as \(n > 30\) **Test Statistic:** \(Z\) **Calculations:** 1. **Mean of Sampling Distribution:** \[ \mu_{\bar{X}} = \mu = 7500 \] 2. **Standard Error:** \[ \sigma_{\bar{X}} = \frac{\sigma}{\sqrt{n}} = \frac{1750}{\sqrt{50}} \approx 247.4874 \] 3. **Test Statistic Value:** \[ Z = \frac{\bar{X} - \mu_{\bar{X}}}{\sigma_{\bar{X}}} = \frac{6820 - 7500}{247.4874} = -2.75 \] **Diagram Explanation:** There is a bell curve representing a normal distribution, centered at the population mean, 7500. The area to the left of the point \(-2.75\) is shaded, indicating the probability \(P(Z \leq -2.75) = 0.0030\). This area corresponds to the lower tail of the distribution, which is significant at this level. **Conclusion:** The probability that the sample mean \(\bar{X}\) is less than or equal to 6820 is very small (0.3%), suggesting that such an observation is unusual if the true population mean is indeed 7500. This outcome may be considered statistically significant depending on the chosen threshold for significance.
### Statistical Analysis of Fishing and Health Data

#### Fishing Time Analysis

**Problem 5: Fishing from Shore vs. Boat**

Is it better to fish from the shore or a boat? Let \( x \) be a random variable representing the number of hours taken to catch a fish. The table below contains the data taken over several months for \( B \) from the shore, and \( A \) from a boat.

| Month | B (shore) | A (boat) |
|-------|-----------|----------|
| Oct   | 1.6       | 1.5      |
| Nov   | 1.8       | 1.4      |
| Dec   | 2.0       | 1.6      |
| Jan   | 3.2       | 2.2      |
| Feb   | 3.9       | 3.3      |
| Mar   | 3.6       | 3.0      |
| Apr   | 3.3       | 3.8      |

Use a 1% level of significance to determine if there is a difference in the population mean hours per fish using a boat compared with fishing from the shore. (This is a paired difference problem.)

#### Hay Fever Rate Analysis

**Problem 6: Age Groups and Hay Fever Rates**

In a location, two random samples were taken concerning the rate of hay fever per 1000 population.

- **Sample 1** (\( n_1 = 14 \)) contained people under 25.
- **Sample 2** (\( n_2 = 16 \)) contained people over 50.

\[
\bar{X}_1 = 109.5, \quad s_1 = 15.41 \\
\bar{X}_2 = 99.36, \quad s_2 = 11.57 \\
\]

Assume that the hay fever rate in each group has an approximately normal distribution. Do the data indicate that the over 50 group has a significantly lower hay fever rate? (Use \( \alpha = 5\% \))

(Note: Several of these problems have been adapted from our text.)

#### Testing Framework

- **Random Variable:** ______________

- **Special considerations/characteristics:** ______________

- **Given:**

- **Question:**

  - **B. What Type:**

  - **Why Justified
Transcribed Image Text:### Statistical Analysis of Fishing and Health Data #### Fishing Time Analysis **Problem 5: Fishing from Shore vs. Boat** Is it better to fish from the shore or a boat? Let \( x \) be a random variable representing the number of hours taken to catch a fish. The table below contains the data taken over several months for \( B \) from the shore, and \( A \) from a boat. | Month | B (shore) | A (boat) | |-------|-----------|----------| | Oct | 1.6 | 1.5 | | Nov | 1.8 | 1.4 | | Dec | 2.0 | 1.6 | | Jan | 3.2 | 2.2 | | Feb | 3.9 | 3.3 | | Mar | 3.6 | 3.0 | | Apr | 3.3 | 3.8 | Use a 1% level of significance to determine if there is a difference in the population mean hours per fish using a boat compared with fishing from the shore. (This is a paired difference problem.) #### Hay Fever Rate Analysis **Problem 6: Age Groups and Hay Fever Rates** In a location, two random samples were taken concerning the rate of hay fever per 1000 population. - **Sample 1** (\( n_1 = 14 \)) contained people under 25. - **Sample 2** (\( n_2 = 16 \)) contained people over 50. \[ \bar{X}_1 = 109.5, \quad s_1 = 15.41 \\ \bar{X}_2 = 99.36, \quad s_2 = 11.57 \\ \] Assume that the hay fever rate in each group has an approximately normal distribution. Do the data indicate that the over 50 group has a significantly lower hay fever rate? (Use \( \alpha = 5\% \)) (Note: Several of these problems have been adapted from our text.) #### Testing Framework - **Random Variable:** ______________ - **Special considerations/characteristics:** ______________ - **Given:** - **Question:** - **B. What Type:** - **Why Justified
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