Suppose x has a distribution with = 10 and 2. (a) If a random sample of size n = 49 is drawn, find μ, and P(10 ≤ x ≤ 12). (Round to two decimal places and the probability to four decimal places.) H = 10 x = 0.286 X P(10 ≤ x ≤ 12) = 0.4999 (b) If a random sample of size n = 55 is drawn, find and P(10 ≤ x ≤ 12). (Round o to two decimal places and the probability to four decimal places.) H = 10 x = 0.270 P(10 ≤ x ≤ 12) = X (c) Why should you expect the probability of part (b) to be higher than that of part (a)? (Hint: Consider the standard deviations in parts (a) and (b).) The standard deviation of part (b) is smaller than ✓ part (a) because of the larger sample size. Therefore, the distribution about μ is narrower ✓

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**Title: Understanding Probability and Sample Distribution**

Suppose \( x \) has a distribution with \( \mu = 10 \) and \( \sigma = 2 \).

**Part (a):**

If a random sample of size \( n = 49 \) is drawn, find \( \mu_{\bar{x}}, \sigma_{\bar{x}} \) and \( P(10 \leq \bar{x} \leq 12) \). (Round \( \sigma_{\bar{x}} \) to two decimal places and the probability to four decimal places.)

- \( \mu_{\bar{x}} = 10 \) (✔️)
- \( \sigma_{\bar{x}} = 0.286 \) (❌)
- \( P(10 \leq \bar{x} \leq 12) = 0.4999 \) (✔️)

**Part (b):**

If a random sample of size \( n = 55 \) is drawn, find \( \mu_{\bar{x}}, \sigma_{\bar{x}} \) and \( P(10 \leq \bar{x} \leq 12) \). (Round \( \sigma_{\bar{x}} \) to two decimal places and the probability to four decimal places.)

- \( \mu_{\bar{x}} = 10 \) (✔️)
- \( \sigma_{\bar{x}} = 0.270 \) (✔️)
- \( P(10 \leq \bar{x} \leq 12) \) (❌)

**Part (c):**

Why should you expect the probability of part (b) to be higher than that of part (a)?

*Hint: Consider the standard deviations in parts (a) and (b).*

The standard deviation of part (b) is smaller than part (a) because of the larger sample size. Therefore, the distribution about \( \mu_{\bar{x}} \) is narrower. (✔️)
Transcribed Image Text:**Title: Understanding Probability and Sample Distribution** Suppose \( x \) has a distribution with \( \mu = 10 \) and \( \sigma = 2 \). **Part (a):** If a random sample of size \( n = 49 \) is drawn, find \( \mu_{\bar{x}}, \sigma_{\bar{x}} \) and \( P(10 \leq \bar{x} \leq 12) \). (Round \( \sigma_{\bar{x}} \) to two decimal places and the probability to four decimal places.) - \( \mu_{\bar{x}} = 10 \) (✔️) - \( \sigma_{\bar{x}} = 0.286 \) (❌) - \( P(10 \leq \bar{x} \leq 12) = 0.4999 \) (✔️) **Part (b):** If a random sample of size \( n = 55 \) is drawn, find \( \mu_{\bar{x}}, \sigma_{\bar{x}} \) and \( P(10 \leq \bar{x} \leq 12) \). (Round \( \sigma_{\bar{x}} \) to two decimal places and the probability to four decimal places.) - \( \mu_{\bar{x}} = 10 \) (✔️) - \( \sigma_{\bar{x}} = 0.270 \) (✔️) - \( P(10 \leq \bar{x} \leq 12) \) (❌) **Part (c):** Why should you expect the probability of part (b) to be higher than that of part (a)? *Hint: Consider the standard deviations in parts (a) and (b).* The standard deviation of part (b) is smaller than part (a) because of the larger sample size. Therefore, the distribution about \( \mu_{\bar{x}} \) is narrower. (✔️)
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