Suppose we have data = = k=1,...,m and corresponding values y [k]k=1, and we want to find a polynomial pr(x) = Σ}_ª¡z³ which is the "best fit" for the given data. We can find such polynomial by finding coefficients {a} that minimizes the sum j=0 m K = [yk - Pn(x)]². k=1 The partial derivatives of K with respect to the coefficients of p, must be zero, i.e. for i = 0,...,n, data Day Temperature 1 87 2 80.3 3 83.3 n m m 4 87.1 m әк 0 2Σ - P(x)] Σα; Σ i+j X k = хкук (1) 5 89.7 Dai k=1 j=0 k=1 k=1 6 90.1 7 82.3 import numpy as np Here, we have the convention that x = 1. Let 8 79.2 def vander(x, degree): 9 65.5 V = [z{\i=1___m_j=0,..., and a = [ai]=0..... 10 64.4 m = len(x) Then system (1) is equivalent to VTVa = VTy. The solution to this gives the coefficient of the polynomial which is the "best fit" for the given data. Find the coefficients of polynomial with degree 3 using QR factorization which is the best fit" for the data. Compute for the value of K. 12215676222 59.8 n-degree +1 60.2 V= np.zeros((m, n)) 13 65.5 14 71.2 for i in range(m): 77.1 for j in range(n): 73.9 69.1 V[i, j] = x[ü] **j 18 58.4 19 63.8 return V 20 73.5 51.1
Suppose we have data = = k=1,...,m and corresponding values y [k]k=1, and we want to find a polynomial pr(x) = Σ}_ª¡z³ which is the "best fit" for the given data. We can find such polynomial by finding coefficients {a} that minimizes the sum j=0 m K = [yk - Pn(x)]². k=1 The partial derivatives of K with respect to the coefficients of p, must be zero, i.e. for i = 0,...,n, data Day Temperature 1 87 2 80.3 3 83.3 n m m 4 87.1 m әк 0 2Σ - P(x)] Σα; Σ i+j X k = хкук (1) 5 89.7 Dai k=1 j=0 k=1 k=1 6 90.1 7 82.3 import numpy as np Here, we have the convention that x = 1. Let 8 79.2 def vander(x, degree): 9 65.5 V = [z{\i=1___m_j=0,..., and a = [ai]=0..... 10 64.4 m = len(x) Then system (1) is equivalent to VTVa = VTy. The solution to this gives the coefficient of the polynomial which is the "best fit" for the given data. Find the coefficients of polynomial with degree 3 using QR factorization which is the best fit" for the data. Compute for the value of K. 12215676222 59.8 n-degree +1 60.2 V= np.zeros((m, n)) 13 65.5 14 71.2 for i in range(m): 77.1 for j in range(n): 73.9 69.1 V[i, j] = x[ü] **j 18 58.4 19 63.8 return V 20 73.5 51.1
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