Suppose the probability that someone drinks iced tea is P (A) = .35, the probability that someone drinks hot tea is P (B) = .25, and the probability that someone doesn’t drink tea is P (C). In addition, P (A∪B∪C) = 1. a) What are the minimum and maximum possible values of P (A ∩B)? b) What are the minimum and maximum possible values of P (C)? c) TRUE or FALSE A, B, and C are mutually exclusive.

Suppose the probability that someone drinks iced tea is P (A) = .35, the probability that someone drinks hot tea is P (B) = .25, and the probability that someone doesn’t drink tea is P (C). In addition, P (A∪B∪C) = 1. a) What are the minimum and maximum possible values of P (A ∩B)? b) What are the minimum and maximum possible values of P (C)? c) TRUE or FALSE A, B, and C are mutually exclusive.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

For mutually exclusive events R₁, R₂, and R3, we have P(R₁) = 0.05, P(R₂) = 0.5, and P(R3) = 0.45. Also, P(Q|R₁) = 0.5, P (Q | R₂) = 0.7, and P (Q | R3) : = 0.4. Find P (R₁ | Q). P(R₁ IQ) = (Type an integer or a simplified fraction.)
For any two events A and B, show that P(ĀOB)=P(B) – P(A B).
Explain with answer
Solve all ,or left it for another expert.
fill up the table
Your friend is pregnant with non-identical triplets. Calculate the probability of each possible combination of the number of sons and daughters that she could have. Note that the birth order is not specified. Express all answers as fractions reduced to the lowest terms, with no spaces (e.g., 1/6). The probability that she will have 3 sons is . The probability that she will have 3 daughters is . The probability that she will have 2 sons and 1 daughter is . The probability that she will have 1 son and 2 daughters is
For mutually exclusive events R₁, R₂, and R₁, we have P(R₁)=0.05, P(R₂) = 0.3, and P(R₂) = 0.65. Also, P(QIR₁) = 0.4, P (Q1R₂) = 0.6, and P(Q|R3) =0.8. Find P (R3 | Q). P (R31Q) = (Type an integer or a simplified fraction.)
Show the work,
am. 104.
the second photo is an example of resolution