Explain with answer (iv) On the assumption that the two events A and B are mutually exclusive, P(A or B)=P(A) + P(B). How does P(A or B) change if the two events are not mutuallyexclusive?(a) P(A) + P(B)] must be multiplied by P(AB)(b) [P(A) + P(B)] must be divided by P(AB)(c) P(AB) must be subtracted from P(A) + P(B)(d) P(AB) must be added to P(A) + P(B)

If two events A and B are mutually exclusive i.e they can not be occur simultaneously then P(A and…

Answered: On the assumption that the two events A…

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN:9780547587776

Author:HOLT MCDOUGAL

Publisher:HOLT MCDOUGAL

Chapter11: Data Analysis And Probability

Section11.9: Independent And Dependent Events

Problem 1E

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The probability that event A or event B will occur is P(A or B)=P(A)+P(B)−P(A or B).
The Addition Rule says that P(A or B) = P(A) + P(B). What must be TRUE about events A and B for this rule to apply? The events must be complements. The events must be disjoint. There must be a positive probability that the events can occur simultaneously. The events must be dependent. The events must be independent.
We are given that P(A | B) = 0.2 and P(A) = 0.9. Since P(A | B) ≠ P(A), the occurrence of event B changes the probability that event A will occur. This implies that A and B are events.So, to determine P(A and B), we can apply the general multiplication rule for events. Recall that P(B) = 0.5. P(A and B) = P(B) · P(A | B) = (0.5) ·
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The Addition Rule for the probability that events A or B or C will occur, P(A or B or C), is given by P(A or B or C)=P(A) + P(B) + P(C) - P(A and B)- P(A and C) - P(B and C) + P(A and B and C) Find P(A or B or C) for the given probabilities. P(A) = 0.32, P(B) = 0.24, P(C) = 0.11 P(A and B) = 0.13, P(A and C) = 0.03, P(B and C) = 0.08 P(A and B and C) = 0.01 P(A or B or C) = montesino P Pearson DELL S Hummert mana SEFERDESSERTS SIEMENS se fa m Next Copyright © 2022 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions Contac
The Addition Rule for the probability that events A or B or C will occur, P(A or B or C), is given by P(A or B or C)=P(A) + P(B) + P(C) - P(A and B)- P(A and C) - P(B and C) + P(A and B and C) Find P(A or B or C) for the given probabilities. P(A)=0.38, P(B) = 0.29, P(C) = 0.12 P(A and B)=0.12, P(A and C) = 0.04, P(B and C) = 0.06 P(A and B and C) = 0.01 P(A or B or C) =
We are given that P(A | B) = 0.4 and P(A) = 0.3. Since P(A | B) ≠ P(A), the occurrence of event B changes the probability that event A will occur. This implies that A and B are ---Select--- not independent independent events.So, to determine P(A and B), we can apply the general multiplication rule for events. Recall that P(B) = 0.9. P(A and B) = P(B) · P(A | B)
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you are givin the information that P(A) = 30 and P(B) = 0.40. Do you have enough information to compute P(A or B)? If you know that events A and B are mutually exclusive, do you have enough information to compute P(A or B)?
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On the assumption that the two events A and B are mutually exclusive, P(A or B)= P(A)+ P(B). How does P(A or B) change if the two events are not mutually exclusive?