Suppose the mean wait-time for a telephone reservation agent at a large airline is 45 seconds. A manager with the airline is concerned that business may be lost due to customers having to wa long for an agent. To address this concern, the manager develops new airline reservation policies that are intended to reduce the amount of time an agent needs to spend with each customer. A random sample of 250 customers results in a sample mean wait-time of 44.4 seconds with a standard deviation of 4.2 seconds. Using a = 0.05 level of significance, do you believe the new polic were effective in reducing wait time? Do you think the results have any practical significance? Determine the null and alternative hypotheses. 45 seconds 45 seconds Ho: H₁: ▼ ▼ Calculate the test statistic. (Round to two decimal places as needed.). Calculate the P-value. P-value= (Round to three decimal places as needed.) State the conclusion for the test. O A. Reject Ho the P-value is less than the a= 0.05 level of significance. OB. Do not reject Ho because the P-value is greater than the a= 0.05 level of significance. OC. Reject Ho because the P-value is greater than the a= 0.05 level of significance. O D. Do not reject Ho because the P-value s less than the a= 0.05 level of significance. State the conclusion in context of the problem. There sufficient evidence at the a= 0.05 level of significance to conclude that the new policies were effective.
Suppose the mean wait-time for a telephone reservation agent at a large airline is 45 seconds. A manager with the airline is concerned that business may be lost due to customers having to wa long for an agent. To address this concern, the manager develops new airline reservation policies that are intended to reduce the amount of time an agent needs to spend with each customer. A random sample of 250 customers results in a sample mean wait-time of 44.4 seconds with a standard deviation of 4.2 seconds. Using a = 0.05 level of significance, do you believe the new polic were effective in reducing wait time? Do you think the results have any practical significance? Determine the null and alternative hypotheses. 45 seconds 45 seconds Ho: H₁: ▼ ▼ Calculate the test statistic. (Round to two decimal places as needed.). Calculate the P-value. P-value= (Round to three decimal places as needed.) State the conclusion for the test. O A. Reject Ho the P-value is less than the a= 0.05 level of significance. OB. Do not reject Ho because the P-value is greater than the a= 0.05 level of significance. OC. Reject Ho because the P-value is greater than the a= 0.05 level of significance. O D. Do not reject Ho because the P-value s less than the a= 0.05 level of significance. State the conclusion in context of the problem. There sufficient evidence at the a= 0.05 level of significance to conclude that the new policies were effective.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Suppose the mean wait-time for a telephone reservation agent at a large airline is 45 seconds. A manager with the airline is concerned that business may be lost due to customers having to wait too
long for an agent. To address this concern, the manager develops new airline reservation policies that are intended to reduce the amount of time an agent needs to spend with each customer. A
random sample of 250 customers results in a sample mean wait-time of 44.4 seconds with a standard deviation of 4.2 seconds. Using a = 0.05 level of significance, do you believe the new policies
were effective in reducing wait time? Do you think the results have any practical significance?
Determine the null and alternative hypotheses.
Ho:
H₁:
▼
=
▼
Calculate the test statistic.
45 seconds
45 seconds
(Round to two decimal places as needed.)
Calculate the P-value.
P-value=
(Round to three decimal places as needed.)
State the conclusion for the test.
OA. Reject Ho because the P-value is less than the a= 0.05 level of significance.
OB. Do not reject Ho because the P-value is greater than the a= 0.05 level of significance.
OC. Reject Ho because the P-value is greater than the a= 0.05 level of significance.
OD. Do not reject Ho because the P-value is less than the a= 0.05 level of significance.
State the conclusion in context of the problem.
There
...
sufficient evidence at the a= 0.05 level of significance to conclude that the new policies were effective.
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