Suppose the heights of the members of a population follow a normaldistribution. If the mean height of the population is 65 inches and thestandard deviation is 3 inches, 68% of the population will have a height withinwhich range?OA 62 inches to 68 inchesOB. 59 inches to 71 inchesC. 53 inches to 77 inchesD. 56 inches to 74 inches

Answered: Image /qna-images/answer/cead1c50-72a5-4080-a89f-bb328219b28d.jpg

Answered: Suppose the heights of the members of a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Which scenario will give you a coefficient of variation of 30%? A. Mean of 30 and standard deviation of 15 B. Mean of 4 and standard deviation of 16 C. Mean of 3 and standard deviation of 3 D. Mean of 10 and standard deviation of 3 Find the range of the given data: 12, 5, 9, 18, 22, 25, 5 A. 5 B. 9 C. 20 D. 25
If the standard deviation of a data set was originally 5, and if each value in the data set was multiplied by 4.8, what would be the standard deviation of the resulting data? O A. 14 OB. 5 OC. 19 O D. 24
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Question 1 1. For the following data: 22, 25, 26, 27, 27, 29, 30, 36, 36, 44. Determine the frequency and plot the column bar. • Calculate the average, standard deviation, mode, median.
D Question 24 The weights of cats is Normally Distributed. The mean weight is 10 lbs with a standard deviation of 0.2 lbs. Draw the normal curve and fill in the cut scores and percentages. Then answer the questions below: Based on a sample of 600 cats, how many would you expect to weigh more than 10.4 lbs? Based on a sample of 600 cats, how many would you expect to weigh at least 9.8 lbs. but not more than 10.2 lbs? Based on a sample of 600 cats, how many would you expect to weigh more than 10 lbs?
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 57.4 degrees. The mean of the frequency distribution is (Round to the nearest tenth as needed.)
Dianne has a choice of two routes to drive to work. She timed her journey along each route on several occasions and the times in minutes are given below:Town route: 15, 16, 20, 28, 21Country route: 19, 21, 20, 22, 18(i) Calculate the mean and standard deviation (to one d. p.) of each set of journey times.(ii) Which route would you recommend? Give a reason.
A. Population ? B. Population mean ? C. Median ? F. IQR ? G. Population standard deviation ?H. population variance ?
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 52.5 degrees. Low Temperature (o F) 40 - 44 45 - 49 50 - 54 55 - 59 60 – 64 D Frequency 2 9. ... The mean of the frequency distribution is degrees. (Round to the nearest tenth as needed.) Which of the following best describes the relationship between the computed mean and the actual mean? O A. The computed mean is close to the actual mean because the difference between the means is more than 5% of the actual mean. B. The computed mean is not close to the actual mean because the difference between the means is less than 5% of the actual mean. C. The computed mean is not close to the actual mean because the difference between the means is more than 5% of the actual mean. D. The computed mean is close to the actual mean because the difference between the means is less than 5% of the actual mean.
Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to P34, the 84th percentile. This is the temperature reading separating the bottom 84% from the top 16%. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents P ? Choose the correct graph below. 84 A. В. OC. D. Ay X The temperature for P84 is approximately (Round to two decimal places as needed.)
A sample of n = 10 scores has a mean of 20. A person with a score of 1 is replaced with a person who has a score of 31. Find the new mean. a.31 b.17 c.21 d.23
Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P6, the 6th percentile. This is the bone density score separating the bottom 6% from the top 94%. Which graph represents Pg? Choose the correct graph below. OA. O B. OD. Q P8

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