Suppose the goal is to estimate the parameter stated in question 3 using a 95% confidence interval with margin of error no larger than 0.048. What is the minimum numberof trick-or-treaters that would need to be selected to allow the calculation of a 95% confidence interval with margin of error no larger than 0.048? It can be assumed forthis problem only that the proportion of all people who went trick-or-treating who received fruit in addition to candy is 0.24 and this number can be used for thisproblem. Which of the following is the correct answer?204.13123.14304.13123305205304124204

Given : Margin of error: ME = 0.048

Answered: Suppose the goal is to estimate the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A simple random sample of 450 residents in the state of New York is taken to estimate the proportion of people who live within 1 mile of a hazardous waste site. If a 95% confidence interval were calculated for a scenario where p = 0.3 and another scenario where p = 0.7, how would the two confidence intervals compare? This cannot be determined from the information given. Since the sample proportion in the second scenario is larger, its confidence interval would be shifted to the right and narrower than the one calculated from the first scenario. Even though the sample proportions are different, the widths of the confidence intervals would be equal. Since the sample proportion in the first scenario is smaller, its confidence interval would be narrower.
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With data from the 2009 National Health Interview Survey, the Centers for Disease Control estimated that 9.4% of U.S. children had asthma. Suppose that 12% of a random sample of 500 U.S. poor children have asthma. We used the estimate from the 2009 National Health Interview Survey to calculate a standard error of 0.013. The data allows the use of a normal model. So we can find an approximate 95% confidence interval for the percentage of all U.S. poor children who have asthma. Which interval is the approximate 95% confidence interval? 1. 0.094 to 0.146 2. 0.107 to 0.133 3. 0.026 to 0.214 4. 0.068 to 0.12
Suppose you take a sample of size 46 from a Normal distribution with unknown population mean and a population standard deviation of 11. You find your sample has mean 406 and intend to use this as an estimate in a confidence interval. If you wish to construct a 95% confidence interval, what margin of error should you use? Give your answer to two decimal places
A sample of size 25 was taken from a very large population. Sample statistics, x¯ and s, were used to find that the 95% confidence interval was (138.616, 163.384). x¯= s=
1. In a study of perception, 110 men are tested and 24 are found to have red/green color blindness (based on data from USA Today). Assume that this was done in a simple random manner. A 95% confidence interval estimate of the proportion of all men with red/green color blindness was found to be 0.14 to 0.30. If we learn that the actual population proportion of men with red/green colorblindness is equal to 0.12, then what can we conclude? A. The confidence interval was wrong. B. We would need to see the sample data to make any conclusions Pick either answer A or B as your answer and show your work to go with it
Based upon the results of the sample in #1, can you say with 95% confidence that your confidence interval contains the true percentage of all adult females registered to vote?
Question 6 Karen wants to advertise how many chocolate chips are in each Big Chip cookie at her bakery. She randomly selects a sample of 41 cookies and finds that the number of chocolate chips per cookie in the sample has a mean of 14.3 and a standard deviation of 2.2. What is the 90% confidence interval for the number of chocolate chips per cookie for Big Chip cookies? Enter your answers accurate to one decimal place (because the sample statistics are reported accurate to one decimal place). Submit Question
1. A 90% confidence interval is wider than a 99% confidence interval using the exact same data. True False ONLY If false, change the underlined portion by putting the correct answer here (leave blank if true): 2. The null hypothesis if you are trying to find out if you have enough evidence to conclude that the population mean is different than 55 would be Ha: µ ≠ 55. True False If false, change the underlined portion by putting the correct answer here (leave blank if true): 3. A p-value of 0.017 provides more evidence against the null hypothesis than a p-value of 0.005. True False ONLY If false, change the underlined portion by putting the correct answer here (leave blank if true):
Question 1: The GPAs of nursing students (p1) were compared to GPAs of student-athletes (p2) were compared. Of a sample of 400 randomly and independently selected nursing students, 75% were placed on honor roll. Of a sample of 100 athletes, 80% of the students were placed on honor roll. Calculated the LOWER bound of the 95% confidence interval for the two samples. Round to the nearest hundredth. Question 2: The GPAs of nursing students (p1) were compared to GPAs of student-athletes (p2) were compared. Of a sample of 400 randomly and independently selected nursing students, 75% were placed on honor roll. Of a sample of 100 athletes, 80% of the students were placed on honor roll. Calculated the UPPER bound of the 95% confidence interval for the two samples. Round to the nearest hundredth. Question 3: Copy of The GPAs of nursing students (p1) were compared to GPAs of student-athletes (p2) were compared. Of a sample of 400 randomly and independently selected nursing…
A college alumni Organization sent a survey to all recent graduates to ask their annual income. 20% of the alumni responded, and their mean annual income was $40,000 with a standard deviation of $10,000. Explain why these data should not be used to construct a confidence interval for the mean annual income of all recent graduates.
Suppose a new treatment for a certain disease is given to a sample of 180 patients. The treatment was successful for 153of the patients. Assume that these patients are representative of the population of individuals who have this disease. Calculate a 98% confidence interval for the proportion successfully treated. (Round the answers to three decimal places.)

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