Question 3 3. Suppose researchers calculated the 95% confidence interval to be (0.4145, 0.4675). What is the correct interpretation of this interval? There is a 95% probability that the true proportion of all U.S. adults who spend more than 20 hours a week on a computer at home lies between 0.4125 and 0.4675. We are 95% confident that the true sample proportion of U.S. adults who spend more than 20 hours a week on a computer at home lies between 0.4125 and 0.4675. We are 95% confident that the true proportion of all U.S. adults who spend more than 20 hours a week on a computer at home lies between 0.4125 and 0.4675. 95% of adults lie between 0.4125 and 0.4675 Question 4 4. Suppose the researchers decided to take a sample of size 200 rather than that of 81. How would this change the margin of error? The margin of error would decrease The margin of error would stay the same The margin of error would increase
Question 3 3. Suppose researchers calculated the 95% confidence interval to be (0.4145, 0.4675). What is the correct interpretation of this interval? There is a 95% probability that the true proportion of all U.S. adults who spend more than 20 hours a week on a computer at home lies between 0.4125 and 0.4675. We are 95% confident that the true sample proportion of U.S. adults who spend more than 20 hours a week on a computer at home lies between 0.4125 and 0.4675. We are 95% confident that the true proportion of all U.S. adults who spend more than 20 hours a week on a computer at home lies between 0.4125 and 0.4675. 95% of adults lie between 0.4125 and 0.4675 Question 4 4. Suppose the researchers decided to take a sample of size 200 rather than that of 81. How would this change the margin of error? The margin of error would decrease The margin of error would stay the same The margin of error would increase
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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Transcribed Image Text:Question 3
3. Suppose researchers calculated the 95%
confidence interval to be (0.4145, 0.4675).
What is the correct interpretation of this
interval?
There is a 95% probability that the true
proportion of all U.S. adults who spend more
than 20 hours a week on a computer at home
lies between 0.4125 and 0.4675.
We are 95% confident that the true sample
proportion of U.S. adults who spend more than
20 hours a week on a computer at home lies
between 0.4125 and 0.4675.
We are 95% confident that the true proportion
of all U.S. adults who spend more than 20 hours
a week on a computer at home lies between
0.4125 and 0.4675.
95% of adults lie between 0.4125 and 0.4675
D Question 4
4. Suppose the researchers decided to take a
sample of size 200 rather than that of 81.
How would this change the margin of
error?
The margin of error would decrease
The margin of error would stay the same
The margin of error would increase

Transcribed Image Text:4:
A study was conducted in order to estimate
the proportion of U.S. adults that use a
computer at home more than 20 hours a week.
Suppose 36 out of a random sample of 81
adults use a computer at home more than 20
hours a week.
Question 1
1. Is the sample size large enough to compute
a confidence interval for the proportion of
U.S. adults who spend more than 20 hours
a week on a home computer?
Yes, because the sample size is greater than 30
Yes, because more than 10 adults did not spend
more than 20 hours a week on a home computer
Yes, because more than 10 adults spent more
than 20 hours a week on a home computer
O Yes, because both np and n(1-p) are greater than
10
Question 2
2. Suppose that p is 0.6 and the standard
error of p is 0.025 and that all conditions
are met. Compute a 95% confidence
interval for the proportion of adults who
spend more than 20 hours a week on a
home computer.
O (0.55, 0.6)
(0.575, 0.625)
(0.551, 0.649)
(0.6, 0.65)
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