the department of public health would like to estimate the proportion of adults who exercise on a regular basis. A previous study estimated the proportion was close to 20% a. How large a sample would be required if they want their results to have a 99% level of confidence and have a maximum error of 1%   b.Suppose a sample of minimum size is chosen. if 23%of those surveyed exercise on a regular basis, find a 99% confidence interval for the proportion of all adults who exercise on a regular basis.

Q: If n = 10, ¯xx¯ = 43, and s = 8, construct a confidence interval at a 90% confidence level. Assume…

A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…

Q: Find the value of the sample size needed if the confidence interval is 95% that the sample…

A: Given that  Margin of error =E =0.04 Sample proportion p^=0.45

Q: If n=30, (x-bar)=38, and s=8, construct a confidence interval at a 90% confidence level. Assume the…

A:

Q: If n=16, ¯xx¯(x-bar)=46, and s=12, construct a confidence interval at a 95% confidence level. Assume…

A: Given n=16 x=46 s=12 CL=95% Data is normally distributed

Q: If X = 114, α= 20, and n = 33, construct a 99% confidence interval estimate for the population mean,…

A: Given data:  Sample Mean = 114 Population standard deviation = 20 Sample size = 33 Confidence level…

Q: mpling process is repeated many time sers who use this social media platfor

A: Option b) is correct.   The estimate is given by p^ =0.458 + 0.5282 = 0.52

Q: If X=70​, σ=14​, and n=61​, construct a 99​% confidence interval estimate of the population​ mean,…

A:

Q: If n=22, ¯xx¯(x-bar)=45, and s=4, construct a confidence interval at a 90% confidence level. Assume…

A: Ans -   Given the level of confidence interval   90 %                      Then   α = 1 - 0.90 =…

Q: If n=31, ¯xx¯(x-bar)=30, and s=10, construct a confidence interval at a 80% confidence level. Assume…

A:

Q: Kim wants to determine a 80 percent confidence interval for the true proportion of high school…

A: Given: Margin of error, E=0.04 Confidence level=80%

Q: If n=31, (x-bar)=49, and s=3, construct a confidence interval at a 80% confidence level. Assume the…

A: Given, Sample size = 31 Sample mean = 49 Sample standard deviation = 3   Since the population…

Q: If n = 22, ¯xx¯ = 36, and s = 14, construct a confidence interval at a 98% confidence level. Assume…

A: From the provided information, Sample size (n) = 22 Sample mean (x̄) = 36 Standard deviation (s) =…

Q: If n = 28, ¯xx¯ = 49, and s = 19, construct a confidence interval at a 90% confidence level. Assume…

A: Given information- Sample size, n = 28 Sample mean, x-bar = 49 Sample standard deviation, s = 19…

Q: Suppose that the a college wants to have an idea of the average SAT score of the incoming freshman…

A: The confidence level is 0.90, the standard deviation is 310 and margin of error E is 50.

Q: construct a confidence interval at a 98% confidence level.

A: Given : n=29 , X-bar=39  , s=11  , α=0.02 Since , the population standard deviation (σ) is unknown.…

Q: If Xbar=81​,S=20​,and n=36​,and assuming that the population is normally​ distributed, construct a…

A:

Q: For the following data, determine if it would be appropriate to find a confidence interval for the…

A: Proportion can be determined by dividing the total number of items in the survey by the number of…

Q: If n=12, (x-bar)=33, and s=16, construct a confidence interval at a 80% confidence level. Assume the…

A:

Q: In a study of government financial aid for college students, it becomes necessary to estimate the…

A: The provided information are: Confidence level = 90% = 0.90 Margin of error (E) = 0.05 From the…

Q: If n = 25, ¯x = 50, and s = 19, construct a confidence interval at a 99% confidence level. Assume…

A:

Q: If n=41n=41, ¯xx¯=36, and s=9s=9, find the margin of error for a 80% confidence level.

A: Answer - Given, Sample size n = 41,    x  = 36    and s = 9               80% confidence interval…

Q: n=31, ¯xx¯(x-bar)=30, and s=5, construct a confidence interval at a 98% confidence level. Assume the…

A:

Q: A public health official in Martin county needs to estimate the average diastolic blood pre…

A: Given: Sample size(n)=132Meanx¯=89Population standard deviationσ=10

Q: If n = 15, ¯x = 50, and s = 9, construct a confidence interval at a 90% confidence level. Assume the…

A:

Q: If n=24, ¯xx¯(x-bar)=49, and s=9, construct a confidence interval at a 80% confidence level. Assume…

A:

Q: In a study of government financial aid for college students, it becomes necessary to estimate the…

A: Solution: From the given information, confidence level is 0.95, p=0.40 and E=0.03.

Q: If n=12, x=47, and s=7, construct a confidence interval at a 98% confidence level. Assume the data…

A: According to the provided information,

Q: If n=13, ¯x(x-bar)=44, and s=3, construct a confidence interval at a 99% confidence level. Assume…

A: Here, n is 13, x-bar is 44, and s is 3. Critical value: Using Excel formula…

Q: Suppose that you are in charge to see if dropping a computer will damage it. You want to find the…

A:

Q: Estimate 95% confidence interval for the proportion of household experiencing burglary in 2010."

A: 25.8 households per 1,000 were the victims of home burglary. These data are obtained from a survey…

Q: I am struggling setting this problem up. Any help would be greatly appreciated! For this…

A: As the information is said to be assumed, so I assumed some values.

Q: Suppose you calculate a 95% confidence interval for a proportion to to be: 0.39 to 0.78. Determine…

A: Given,   Lower bound = 0.39​ Upper bound = 0.78   Here, we use to determine the margin of error.

Q: If n=14, (x-bar)=46, and s=18, construct a confidence interval at a 80% confidence level. Assume the…

A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…

Q: If n = 15, ¯xx¯ = 43, and s = 11, construct a confidence interval at a 98% confidence level. Assume…

A: Given that, The degree of freedom is, Critical values: The t-critical values for a two-tailed…

Q: Cora wants to determine a 90% confidence interval for the true proportion of high school students in…

A: Confidence level=90%Margin of error(E)=0.02Assuming that we have no prior estimate of the proportion…

Q: If n=41, ¯x=39, and s=16, construct a confidence interval at a 99% confidence level. Assume the data…

A: Given that  Sample size (n) = 41 Sample mean (x¯) = 39 Sample standard deviation (s) = 16 Confidence…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.