Suppose the formation of dinitrogen pentoxide proceeds by the following mechanism: step elementary reaction rate constant 1 NO, (g) + 0, (g) → NO, (g) + 0, (g) k1 2 NO, (g) + NO, (g) → N,0, (g) k2 Suppose also k, « k,. That is, the first step is much slower than the second. Write the balanced chemical equation for the overall chemical reaction. Write the experimentally- observable rate law for the overall chemical reaction. rate = k Note: your answer should not contain the concentrations of any intermediates.

Suppose the formation of dinitrogen pentoxide proceeds by the following mechanism: step elementary reaction rate constant 1 NO, (g) + 0, (g) → NO, (g) + 0, (g) k1 2 NO, (g) + NO, (g) → N,0, (g) k2 Suppose also k, « k,. That is, the first step is much slower than the second. Write the balanced chemical equation for the overall chemical reaction. Write the experimentally- observable rate law for the overall chemical reaction. rate = k Note: your answer should not contain the concentrations of any intermediates.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Nitrogen dioxide is a highly reactive gas! Determine the rate law and the value of k for the following reaction using the data provided: NO,(g) + O,(g) – NO,(g) + 0,(g) (w) P'ONI [0,1 (M) Initial Rate (M' s) 0.10 0.10 0.25 0.33 0.66 1.42 2.84 7.10 0.66 O Rate = 227 M25SINO,10j5 O Rate = 130 M2 s'[NO,10.J O Rate = 430 M2 s 'INO,ř10.] O Rate = 1380 M2.5 5INO, 10,1 O Rate = 43 M SINO,1O,]
Solution
Consider the following general reaction for which gases A and B are mixed in a constant volume container: A(g) + B(g) -> C(g) + D(g) Match what happens to the rate of the reaction under the following changes: (consider each change separately) v all of gas B is removed from the container more gas A is added to the container the temperature of the container is increased there is no change to the reaction rate ya catalyst is added to the container I. the reaction proceeds at a faster rate v gas D is also added to the container the reaction proceeds at a slower rate II. some of gas B is removed from the container Iy the reaction does not proceed at all the volume of the container is increased
[4] Consider the following mechanism for the reaction of nitric oxide and hydrogen: kı 2NO(g)+ H2(g) → N;O(g) + H¿O(g) slow k2 N,0(g) + H2(g) → N2(g) + H2O(g) fast (a) Write an equation for the overall reaction. (b) Write the theoretical rate law for the above mechanism. (c) Is a catalyst involved in the above mechanism? If so, what is it? (d) Are there any reaction intermediates? If so, list them.
18. Which of these reactions appear to involve a catalyst? In those cases where a catalyst is present, tell whether it is homogeneous or heterogeneous. a) CH,COOCH,(aq) + H,O(() CH,COOH(aq) + CH,OH(aq) Rate = k[CH,COOCH,[H,O"] b) H;(g) +1(g) - Rate = k[H,][I,] +2 HI(g) %3D
Consider the following elementary reaction: (g) (g) Suppose we let stand for the rate constant of this reaction, and stand for the rate constant of the reverse reaction. Write an expression that gives the equilibrium concentration of in terms of , , and the equilibrium concentration of .
Writing the rate law implied by a simple mechanism with an initial slow... Suppose the formation of nitryl fluoride proceeds by the following mechanism: elementary reaction step 1 NO₂ (g) +F₂ (g) 2 k₁ k₂ 2 F (g) + NO₂(g) → NO₂F (g) Suppose also k₁ « k₂. That is, the first step is much slower than the second. Write the balanced chemical equation for the overall chemical reaction. Write the experimentally- observable rate law for the overall chemical reaction. NO₂F (g) +F (g) Note: your answer should not contain the concentrations of any intermediates. rate constant rate = k 0+ 00 X Ś
Suppose the formation of nitryl fluoride proceeds by the following mechanism: step elementary reaction 1 NO₂ (g) +F₂ (g) → NO₂F (g)+F (g) 2 F (g) + NO₂ (g) → NO₂F (g) Suppose also k₁ << k₂. That is, the first step is much slower than the second. Write the balanced chemical equation for the overall chemical reaction. Write the experimentally- observable rate law for the overall chemical reaction. Note: your answer should not contain the concentrations of any intermediates. 0 rate = & rate constant k₁ k₂
Suppose the reaction between nitric oxide and oxygen proceeds by the following mechanism: step elementary reaction rate constant 1 NO(g) + O,(g) –→ NO2(g) + O(g) k1 NO(g) + O(g) → NO2(g) Suppose also k,«k,. That is, the first step is much slower than the second. Write the balanced chemical equation for the overall chemical reaction: Write the experimentally- observable rate law for the overall chemical reaction. rate = k || Note: your answer should not contain the concentrations of any intermediates. Express the rate constant k for the overall chemical reaction in terms of k1, k2, and (if necessary) the rate constants k.1 and k-2 for k = | %3D the reverse of the two elementary reactions in the mechanism.
the rate law for the reaction represented above is experimentally determines to be rate=k[N2O] which of the following explain s why increasing the initial concentration of N2O at a constance temperature increases the reaction rate
Suppose the formation of nitrogen dioxide proceeds by the following mechanism: elementary reaction 2NO (g) → N₂O₂ (g) step 1 2 N₂O₂(g) + O₂ (g) Write the balanced chemical equation for the overall chemical reaction. Write the experimentally- observable rate law for the overall chemical reaction. 2NO₂ (g) Suppose also k₁ « k₂. That is, the first step is much slower than the second. << Note: your answer should not contain the concentrations of any intermediates. rate constant 0 k₁ k₂ rate = k 1-0 010 X S