Suppose that X~ N(−11.6, 19.2) and that Z follows the standard normal distribution. Part 1. a) Compute the value of z such that P(X < 27.42) = P(Z < 2). 2= Number (Enter your answer correct to at least 5 decimal places) b) Hence, compute P(X < 27.42). P(X < 27.42) = (Enter your answer correct to at least 3 significant figures) Part 2. Now, suppose that for a certain number x, P(X > x) = 0.75. c) Compute the value of z such that P(Z < z) = 0.75. 2= Number (Enter your answer correct to at least 5 decimal places) d) Hence, compute the value of such that P(X > x) = 0.75. x = Number (Enter your answer correct to at least 3 decimal places)

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Suppose that X~ N(-11.6, 19.2) and that Z follows the standard normal distribution.
Part 1.
a) Compute the value of z such that P(X < 27.42) = P(Z < 2).
2 = Number
(Enter your answer correct to at least 5 decimal places)
b) Hence, compute P(X < 27.42).
P(X < 27.42) =
=
(Enter your answer correct to at least 3 significant figures)
Part 2
Now, suppose that for a certain number x, P(X > x) = 0.75.
c) Compute the value of z such that P(Z < z) = 0.75.
z =
Number
(Enter your answer correct to at least 5 decimal places)
d) Hence, compute the value of a such that P(X > x) = 0.75.
x = Number
(Enter your answer correct to at least 3 decimal places)
Transcribed Image Text:Suppose that X~ N(-11.6, 19.2) and that Z follows the standard normal distribution. Part 1. a) Compute the value of z such that P(X < 27.42) = P(Z < 2). 2 = Number (Enter your answer correct to at least 5 decimal places) b) Hence, compute P(X < 27.42). P(X < 27.42) = = (Enter your answer correct to at least 3 significant figures) Part 2 Now, suppose that for a certain number x, P(X > x) = 0.75. c) Compute the value of z such that P(Z < z) = 0.75. z = Number (Enter your answer correct to at least 5 decimal places) d) Hence, compute the value of a such that P(X > x) = 0.75. x = Number (Enter your answer correct to at least 3 decimal places)
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