Attempt only if you can solve all par I'll upvote your answer, otherwise I downvote Suppose that the weight of an newborn fawn is Unifo distributed between 2.3 and 3 kg. Suppose that a ne fawn is randomly selected. Round answers to 4 decir places when possible. a. The mean of this distribution is b. The standard deviation is c. The probability that fawn will weigh exactly 2 P(x = 2.9) = d. The probability that a newborn fawn will be w between 2.6 and 2.8 is P(2.6 < x < 2.8) = e. The probability that a newborn fawn will be w more than 2.44 is P(x > 2.44) f. P(x > 2.6 | x < 2.9) = g. Find the 76th percentile.
Attempt only if you can solve all par I'll upvote your answer, otherwise I downvote Suppose that the weight of an newborn fawn is Unifo distributed between 2.3 and 3 kg. Suppose that a ne fawn is randomly selected. Round answers to 4 decir places when possible. a. The mean of this distribution is b. The standard deviation is c. The probability that fawn will weigh exactly 2 P(x = 2.9) = d. The probability that a newborn fawn will be w between 2.6 and 2.8 is P(2.6 < x < 2.8) = e. The probability that a newborn fawn will be w more than 2.44 is P(x > 2.44) f. P(x > 2.6 | x < 2.9) = g. Find the 76th percentile.
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![Attempt only if you can solve all parts
I'll upvote your answer, otherwise I'll
downvote
Suppose that the weight of an newborn fawn is Uniformly
distributed between 2.3 and 3 kg. Suppose that a newborn
fawn is randomly selected. Round answers to 4 decimal
places when possible.
a. The mean of this distribution is
b. The standard deviation is
c. The probability that fawn will weigh exactly 2.9 kg is
P(x = 2.9) =
d. The probability that a newborn fawn will be weigh
between 2.6 and 2.8 is P(2.6 < x < 2.8) =
e. The probability that a newborn fawn will be weigh
more than 2.44 is P(x > 2.44) =
f.
P(x > 2.6 | x < 2.9) =
g. Find the 76th percentile.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F43ae085c-d290-4479-b368-6ccaf2800b90%2Fcce90539-96f2-4b75-86b1-f4a39f127813%2Foiuq5th_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Attempt only if you can solve all parts
I'll upvote your answer, otherwise I'll
downvote
Suppose that the weight of an newborn fawn is Uniformly
distributed between 2.3 and 3 kg. Suppose that a newborn
fawn is randomly selected. Round answers to 4 decimal
places when possible.
a. The mean of this distribution is
b. The standard deviation is
c. The probability that fawn will weigh exactly 2.9 kg is
P(x = 2.9) =
d. The probability that a newborn fawn will be weigh
between 2.6 and 2.8 is P(2.6 < x < 2.8) =
e. The probability that a newborn fawn will be weigh
more than 2.44 is P(x > 2.44) =
f.
P(x > 2.6 | x < 2.9) =
g. Find the 76th percentile.
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