Suppose that the TSH (Thyroid Stimulating Hormone) levels among healthy individuals are normally distributed with a mean of 3.3unitsmLexactly 95% of healthy individuals have TSH levels below 5.9your intermediate computations to at least four decimal places. Round your answer to at least two decimal places.0unitsmLExplanationCheckXSOL - COunitsmLFind the standard deviation of the distribution of TSH levels of healthy individuals. CarrySuppose also thatW2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessi

given data,normal distributionμ=3.3p(x<5.9)=0.95∴p(Z<zc)=0.95 ∴ zc =1.645 [ from…

Answered: Suppose that the TSH (Thyroid…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. Find the x-score that corresponds to a z-score of 2.33. O A. 139.55 B. 142.35 OC. 125.95 D. 134.95 nswer. DII F11 F10 公

Use the formula to find the standard error of the distribution of differences in sample means, I1 – X2. Samples of size 110 from Population 1 with mean 82 and standard deviation 14 and samples of size 80 from Population 2 with mean 76 and standard deviation 17 Round your answer for the standard error to two decimal places. standard error = i
In a particular statistics exam, the 10th percentile of final exam score is 59, and the 90th percentile of final exam score is 93. A histogram of the scores approximately follows the normal curve. What is the approximate standard deviation of the final exam scores? Hints: What is the z value in the normal table that gives you closest to 80% of the area between -z and z? Now what does that tell you about the number of SDs in between 59 inches and 93 inches? You might find it helpful to draw a picture of the normal curve with original units and standard units. 13.1 26.2 17.2 6.5
Answer d, e, & f.
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table, Click to view page 2 of the table. Step 1 теan(u) s tan dard o 90 115 The area of the shaded region is (Round to four decimal places as needed.) Step 2 Required pr X-µ = P = P (Z < 1 = P (Z < 2 = 0.9773 Enter your answer in the answer box and then click Check Answer. %3D All parts showing Clear All Final Check P Type here to search hp
uestion 2: Write uses of the standard deviation
Calcium levels in people are normally distributed with a mean of 9.7 mgdL and a standard deviation of 0.5 mgdL . Individuals with calcium levels in the bottom 10% of the population are considered to have low calcium levels. Find the calcium level that is the borderline between low calcium levels and those not considered low. Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.
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Calcium levels in people are normally distributed with a mean of 9.3 mg and a standard deviation of 0.5 mg Individuals with calcium levels in the bottom dL TP 15% of the population are considered to have low calcium levels. Find the calcium level that is the borderline between low calcium levels and those not considered low. Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place. mg dL Continue acer esc & 24 % 8. @ 6 3 4 r
Please do not give solution in image format thanku The heat evolved in calories per gram of a cement mixture is approximately normally distributed. The mean is thought to be 70, and the standard deviation is 2. You wish to test H0 : μ =70 versus H1 : μ ≠70 with a sample n = 5 specimens. Find β for the case where the true mean heat evolved is 73. Use the α that you calculated in question 6. Report to three digits after decimal point Problem #6: α= 0.907
The Z-score tells you the number of standard deviations away from the mean (and in what direction) a data value is. The formula: Z = *- can be used to find the Z-score for a single member of the population. Notice X - μ tells you the signed distance the data value (X) is from the mean. When you divide that by the size of each chunk (the standard deviation) you are measuring the distance in units of the size of the standard deviations (how many standard deviations fit in the distance between the data value and the mean) - which gives you the Z-score. The formula X = μ+Z.o can be used to find the value in the population when given the Z-score (signed number of standard deviations). Notice that Z. tells you how far from the mean the data value is (since Z is the number of standard deviations and is the size of each standard deviation the product tells the total distance). So adding the distance from the mean to the mean gives the location along the number line for the data value. A…

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