Calcium levels in people are normally distributed with a mean of 9.5 mg/dL and a standard deviation of 0.4 mg/dL. Individuals with calcium levels in the bottom 15% of the population are considered to have low calcium levels. Find the calcium level that is the borderline between low calcium levels and those not considered low. Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.[Input box for answer in mg/dL]There is no graph or diagram associated with the question.

# given : calcium level of people follow normal distribution with mean =9.5 mg/dl and standard…

Answered: mg and a standard deviation of 0.4 dL…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Answer a, b, c, d. For the test procedure and p-value use the second image
STATISTICS (THUMBS UP WILL BE GIVEN. PLEASE WRITE THE COMPLETE SOLUTION. DO NOT USE EXCEL OR SOFTWARE. DO NOT SHORTCUT. MANUAL COMPUTATIONS NEEDED. SEE THE ATTACHED IMAGE FOR THE AREAS UNDER NORMAL CURVE IF NECESSARY) The mean life of a tire is 30 000 km. The standard deviation is 2000 km. a. About 68% of all tires will have a life between km and km. b. What percent of the tires will have a life that exceeds 26 000 km? c. If a company purchased 2000 tires, how many tires would you expect to last more than 28 000 km?
Answer the question. Show all the steps, not only the final answer. if possible, sketch a little diagram to clearly see the area under the normal curve 3. To see if young men ages 8-17 spend per month more or less than the national average of $24.44 to purchase illegal drugs, the manager surveyed 33 young men and found the average amount spent per month for illegal drugs was $22.97. The standard deviation of the sample was $3.70. At α = 0.02, can it be concluded that the average amount spent per month for illegal drugs is not equal to the national average of $24.44?
The blood pressure in millimeters was measured for a large sample of people. The average pressure is 140 mm, and the SD of the measurements is 20 mm. The histogram looks reasonably like a normal curv Use the normal curve to estimate the following percentages. Choose the answer that is closest to being correct. A 19.1% B 30.9% C 38.2% D 69.1% E 68.27% A The percentage of people with blood pressure between 130 and 150 mm. B The percentage of people with blood pressure between 140 and 150 mm. D The percentage of people with blood pressure over 150 mm.
The time to complete an exam is approximately Normal with a mean of 48 minutes and a standard deviation of 7 minutes. The bell curve below represents the distribution for testing times. The scale on the horizontal axis is equal to the standard deviation. Fill in the indicated boxes. H = 48 o = 7 H- 30 H-20 μ+2σ μ+ 3
Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P15, the 15th percentile. This is the bone density score separating the bottom 15% from the top 85%. Which graph represents P15? Choose the correct graph below. O A. 1 P15 Q The bone density score corresponding to P15 is (Round to two decimal places as needed.) B. P15 Q Q -C*** O C. A P15 O D. A P15 Q
Sketch a standard normal curve and shade the area that lies to the left of a. 2.15, b. - 1.61, c. 0, and d. - 7. Then determine the area under the standard normal curve that lies in the area of interest for each part. Click here to view page 1 of the normal distribution table. Click here to view page 2 of the normal distribution table. c. Sketch a standard normal curve and shade the area under the curve that lies to the left of 0. Choose the correct graph below. A. 0 Z G OB. 0 The area to the left of 0 is (Round to four decimal places as needed.) O C. -1 0 O D. -1 0 Time Remaining: 01:09:16 Next
K mly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P2. the 2nd percentile. This is the bone density score separating the bottom 2% from the top 98%. Which graph represents P₂? Choose the correct graph below. O A. OB. The bone density score corresponding to P₂ is. (Round to two decimal places as needed.) P₂ O C. P2 Q O D. P₂
Use the standard normal table to find the z-score that corresponds to the cumulative area 0.0072. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. LOADING... Click to view page 2 of the standard normal table. LOADING... z=enter your response here (Type an integer or decimal rounded to three decimal places as needed.)
Answer the question. Show all the steps, not only the final answer. if possible, sketch a little diagram to clearly see the area under the normal curve. 1. A major research study concluded that the mean number of times that adolescents had engaged in vandalism during the previous 12 months was 3.5 times. We believe the true population mean to be less than this. After collecting our own sample of 36 adolescents, we find that the mean number of times they have vandalized property during a l-year period wasX̅ = 2.9 with a standard deviation equal to .7. Perform all ofthe procedures necessary for conducting a hypothesis test based on our assumption. What do you conclude? Set your alpha level at .05.
Use a table of cumulative areas under the normal curve to find the z-score that corresponds to the given cumulative area. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. If convenient, use technology to find the z-score. 0.05 Click to view page 1 of the table. Click to view page 2 of the table. The cumulative area corresponds to the z-score of (Round to three decimal places as needed.) Standard Normal Table (Page 1) Z 0.09 0.08 0.07 0.06 0.05 0.04 0.03 0.02 0.01 0.00 -3.4 0.0002 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 -3.3 0.0003 0.0004 0.0004 0.0004 0.0004 0.0004 0.0004 0.0005 0.0005 0.0005 - 3.2 0.0005 0.0005 0.0005 0.0006 0.0006 0.0006 0.0006 0.0006 0.0007 0.0007 - 3.1 0.0007 0.0007 0.0008 0.0008 0.0008 0.0008 0.0009 0.0009 0.0009 0.0010 -3.0 | 0.0010 0.0010 0.0011 0.0011 0.0011 0.0012 0.0012 0.0013 0.0013 0.0013 -2.9 0.0014 0.0014 0.0015…
Use the standard normal table to find the z-score that corresponds to the given percentile. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries use the z-score halfway between the corresponding z-scores. If convenient, use technology to find the z-score. P 25 Click to view page 1 of the table. Click to view page 2 of the table. The z-score that corresponds to P25 is (Round to two decimal places as needed.)

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