Homework Help is Here – Start Your Trial Now!
Math
Statistics
Suppose that the population of the number of hours slept by all college students the night before finals is approximately normally distributed. A report claimed that the mean of this population is 6.86 hours. As a student wellness advocate, you want to test this claim, so you select a random sample of 14 college students and record the number of hours each slept the night before finals. Follow the steps below to construct a 90% confidence interval for the population mean of all the numbers of hours slept by college students the night before finals. Then state whether the confidence interval you construct contradicts the report's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results for your random sample. Take Sample Sample size: 0 Point estimate: 0 Sample standard deviation: 0 Critical value: 0 Number of students Compute 14 Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 90% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute". Sample mean 6.517 Standard error: Margin of error: Sample standard deviation 90% confidence interval: 1.793 Ś Critical values 0.005=3.012 ¹0.010 2.650 ¹0.025 2.160 10.050 1.771 ¹0.100 1.350

Suppose that the population of the number of hours slept by all college students the night before finals is approximately normally distributed. A report claimed that the mean of this population is 6.86 hours. As a student wellness advocate, you want to test this claim, so you select a random sample of 14 college students and record the number of hours each slept the night before finals. Follow the steps below to construct a 90% confidence interval for the population mean of all the numbers of hours slept by college students the night before finals. Then state whether the confidence interval you construct contradicts the report's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results for your random sample. Take Sample Sample size: 0 Point estimate: 0 Sample standard deviation: 0 Critical value: 0 Number of students Compute 14 Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 90% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute". Sample mean 6.517 Standard error: Margin of error: Sample standard deviation 90% confidence interval: 1.793 Ś Critical values 0.005=3.012 ¹0.010 2.650 ¹0.025 2.160 10.050 1.771 ¹0.100 1.350

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
See similar textbooks
icon
Related questions
Question
Suppose that the population of the number of hours slept by all college students the night before finals is approximately normally distributed. A report claimed that the mean of this population is 6.86 hours. As a student wellness advocate, you want to test this claim, so you select a random sample of 14 college students and record the number of hours each slept the night before finals. Follow the steps below to construct a 90% confidence interval for the population mean of all the numbers of hours slept by college students the night before. finals. Then state whether the confidence interval you construct contradicts the report's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results for your random sample. Take Sample Sample size: 0 Point estimate: 0 Sample standard deviation: 0 Critical value: 0 Number of students Compute 14 Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 90% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute". Sample mean 6.517 Standard error: Margin of error: Sample standard deviation 90% confidence interval: 1.793 Ś Critical values ¹0.005=3.012 0.010 2.650 ¹0.025 2.160 10.050 1.771 0.100 1.350
Transcribed Image Text:Suppose that the population of the number of hours slept by all college students the night before finals is approximately normally distributed. A report claimed that the mean of this population is 6.86 hours. As a student wellness advocate, you want to test this claim, so you select a random sample of 14 college students and record the number of hours each slept the night before finals. Follow the steps below to construct a 90% confidence interval for the population mean of all the numbers of hours slept by college students the night before. finals. Then state whether the confidence interval you construct contradicts the report's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results for your random sample. Take Sample Sample size: 0 Point estimate: 0 Sample standard deviation: 0 Critical value: 0 Number of students Compute 14 Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 90% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute". Sample mean 6.517 Standard error: Margin of error: Sample standard deviation 90% confidence interval: 1.793 Ś Critical values ¹0.005=3.012 0.010 2.650 ¹0.025 2.160 10.050 1.771 0.100 1.350
(b) Based on your sample, graph the 90% confidence interval for the population mean of all the numbers of hours slept by college students the night before finals. (c) • Enter the values for the lower and upper limits on the graph to show your confidence interval. For the point (), enter the claim 6.86 from the report. 0.000 0.000 2.000 90% confidence interval: 4.000 5.000 6.000 8.000 Does the 90% confidence interval you constructed contradict the claim made in the report? Choose the best answer from the choices below. X 10.000 10.000 No, the confidence interval does not contradict the claim. The mean of 6.86 hours from the report is inside the 90% confidence interval. O No, the confidence interval does not contradict the claim. The mean of 6.86 hours from the report is outside the 90% confidence interval. Yes, the confidence interval contradicts the claim. The mean of 6.86 hours from the report is inside the 90% confidence interval. Yes, the confidence interval contradicts the claim. The mean of 6.86 hours from the report is outside the 90% confidence interval.
Transcribed Image Text:(b) Based on your sample, graph the 90% confidence interval for the population mean of all the numbers of hours slept by college students the night before finals. (c) • Enter the values for the lower and upper limits on the graph to show your confidence interval. For the point (), enter the claim 6.86 from the report. 0.000 0.000 2.000 90% confidence interval: 4.000 5.000 6.000 8.000 Does the 90% confidence interval you constructed contradict the claim made in the report? Choose the best answer from the choices below. X 10.000 10.000 No, the confidence interval does not contradict the claim. The mean of 6.86 hours from the report is inside the 90% confidence interval. O No, the confidence interval does not contradict the claim. The mean of 6.86 hours from the report is outside the 90% confidence interval. Yes, the confidence interval contradicts the claim. The mean of 6.86 hours from the report is inside the 90% confidence interval. Yes, the confidence interval contradicts the claim. The mean of 6.86 hours from the report is outside the 90% confidence interval.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman
SEE MORE TEXTBOOKS