Suppose that SCR is a non-empty set which is bounded below. Define a set R by R= {bER| b is a lower bound for S}. Prove that sup R = inf S.
Suppose that SCR is a non-empty set which is bounded below. Define a set R by R= {bER| b is a lower bound for S}. Prove that sup R = inf S.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Can you please provide a bit more details to the first part of the proof where L=SupR.
How do you know that sup R is a lower bound for S?
How do you know that it is greater than or equal to every other lower bound?

Transcribed Image Text:Suppose that SCR is a non-empty set which is bounded below. Define
a set R by
R= {bER| b is a lower bound for S}.
Prove that sup R = inf S.

Transcribed Image Text:Given that,
SCIR
is a Non-empty set which is bounded below.
a set R by :
{
bEIR | b is a lower bound for s
int s.
We have to Prove, Sup R
Since,
and define
Then
and
S is Bounded below, so I bo E IR
bo is a lower bound for s.
R is
Non empty
bo & R
More oven
9
and
R =
XER
i.e.
This
= R is
Every
has
Thus, By Supremum Property of IR g
a
R has
and
x ≤ 3
is True for all XER
Bounded
above
b ≤ L ;
L = Sup R
and
Non empty bonded above Subset of IR
Supremum in IR.
a supremum.
VBER
(11) since,
every
and
L = Sup R
This, It shows that,
L =
Hence, by (*) & (**)
SE S
SES
We
x is lower bound for 5.
get
Sup R = inf 5
Say
Sneh that
L is a lower bound of S
L any lower bound of S.
inf S
(Proved)
L
as Lis
от uрреr
for R.
is an upper bound of R
L≤8 for every
se s.
*
bound
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