Q1Suppose that language LC {a}*. For which of the following options does L = L*?OL= {A, a, aa, aaa, aaaa, ...}(any length string of a's)OL= {A, aa, aaaa, aaaaaa, ...}(even length strings of a's)OL= {a, aaa, aaaaa, ...} (odd length strings of a's)OL= {A}(only the empty string)

This question comes from Theory of Computation which is a paper of Computer Science. Let's discuss…

Suppose that language LC {a}*. For which of the following options does L = L*? OL= {A, a, aa, aaa, aaaa, ...} OL= {A, aa, aaaa, aaaaaa, ...} OL= {a, aaa, aaaaa,...} (odd length strings of a's) OL= {A} (only the empty string) (any length string of a's) (even length strings of a's)

Suppose that language LC {a}. For which of the following options does L = L? OL= {A, a, aa, aaa, aaaa, ...} OL= {A, aa, aaaa, aaaaaa, ...} OL= {a, aaa, aaaaa,...} (odd length strings of a's) OL= {A} (only the empty string) (any length string of a's) (even length strings of a's)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

C++
The following two languages over {a,b} L1: All strings that contains at least two 'b's L2: All strings that has an 'a' as the second to last character of the string
#7
In Haskell Language write matchEmpty, which determines whether the language for a regular-- expression includes the empty string.matchEmpty :: RE symbol -> BoolmatchEmpty = ?-- Note that the type signature does not restrict symbol to types with-- equality testing, so we cannot use match or match' to check whether the-- empty string is allowed.---- matchEmpty r = match r [] -- type error---- Similarly, we cannot use generate' and check whether the first string-- it provides is the empty string.---- Finally, while generate has the proper type, we cannot use it to write a-- function that always terminates, as we cannot conclude that the empty-- string is not present until we have examined every string.---- *HW3> matchEmpty (getRE "e")-- True-- *HW3> matchEmpty (getRE "abc*")-- False-- *HW3> matchEmpty (getRE "a*")-- True-- *HW3> matchEmpty (getRE "0")-- False-- *HW3> matchEmpty (getRE "0*")-- True NOTE: Above are a few examples of what the output will look like. All…
1. {w E {0, 1} *: w begins with 1 and, when interpreted as a binary number, is a multiple of 5} (since this DFA uses alphabet {0,1}, please flip our conventions and use states a, b, c, ...). *NOTE: Also include the language accepted by DFA as a set. 2. {w| w starts with an a and has at most one b} Draw DFA for each and make intersection of them. i.e, a. 1 DFA for start with an a b. 1 DFA for has at most one b c. 1 DFA for intersection of both of a and b
OZ PROGRAMMING LANGUAGE Develop a function {MapTuple T F} that returns a tuple that has the same width and label as the tuple T with its fields mapped by the function F. For example, local fun {Sq X} X*X end in {MapTuple a(1 2 3) Sq} end should return a(1 4 9). Hint: A tuple is constructed with {MakeTuple L N}, where L is the label and N is the width of the tuple.
Write a program in C programming language that takes two arguments at the command line, both strings. The program checks to see whether or not the second string is a substring of the first (without using the substr -- or any other library -- function). One caveat: any * in the second string can match zero or more characters in the first string, so if the input were abcd and the substring was a*c, then it would count as a substring. Also, include functionality to allow an asterisk to be taken literally if preceded by a \, and a \ is taken literally except when preceding an asterisk.
The following two languages over {0,1} L1: All strings that begin in '00' L2: All strings that have the substring '1' embedded.
5. Design an FSM over the alphabet (0, 1) that accepts strings that do NOT have 111 as a substring. For example: 1011 and 000110 will be accepted but 011100 and 111101 will not.
Specification: Read sentences from the user until * is entered. Show the number of words in each sentence that contain a stretch of non-z characters with exactly 2 vowels. A stretch starts from the start of the word or after a 'z'. A stretch terminates just before another 'z' or at the end of the word. Examples: 1. Matching words: zoo, azozooza, GONZALEZ 2. Non-matching words: ozo, azoooza The sentences contain no punctuation, the words are separated by one or more spaces, and the characters may be upper or lower case. Keep reading sentences until the user enters "*". Sample I/O: Sentence: azoooza azooza zoo azoo Matching words = 3 Sentence: GONZALEZ passes the ball to VAZQUEZ Matching words = 3 Sentence: azozototzeti Matching words = 1 Sentence: * Done
I need help creating this C++ parser program that follows these rules in the image below.
Write a javascript function that takes a string as a parameter and returns the first character that is not repeated in the string. function nonRepeatingChar(str) { I/returns the first non-repeating character in str }