Suppose that in a random selection of 100 colored candies, 29% of them are blue. The candy company claims that the percentage of blue candies is equal to 22%. Use a 0.10 significance level to test that claim. OA. Ho: p=0.22 H₁: p<0.22 B. Ho: p=0.22 H₁: p=0.22 OC. Ho: p= 0.22 H₁: p>0.22 OD. Ho: p 0.22 H₁: p = 0.22 U
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- The table below summarizes data from a survey of a sample of women. Using a 0.05 significance level, and assuming that the sample sizes of 900 men and 400 women are predetermined, test the claim that the proportions of agree/disagree responses are the same for subjects interviewed by men and the subjects interviewed by women. Does it appear that the gender of the interviewer affected the responses of women? Q Women who agree Women who disagree Gender of Interviewer Man 555 345 Woman 318 82 Identify the null and alternative hypotheses. Choose the correct answer below. A. Ho: The proportions of agree/disagree responses are the same for the subjects interviewed by men and the subjects interviewed by women. H₁: The proportions are different. B. Ho: The proportions of agree/disagree responses are different for the subjects interviewed by men and the subjects interviewed by women. H₁: The proportions are the same. OC. Ho: The response of the subject and the gender of the subject are…3. Consider the following competing hypotheses: (You may find it useful to reference the appropriate table: z table or ttable) Hypotheses: Hg: HD s 6; HA: HD > 6 Sample results: 01:05:54 d = 8.2, sp = 7.2, n = 11 The following results are obtained using matched samples from two normally distributed populations: a. Calculate the value of the test statistic, assuming that the sample difference is normally distributed. (Negative value should be indicated by a minus sign. Round final answer to 3 decimal places.) Test statistic b. Find the p-value. O pvalue Picture 0.10 0.05 Picture p-value < 0.10 O 0.025 Picture p-value < 0.05 0.01 Picture p-value < 0.025 O p-value < 0.01Suppose that you have to decide if the mean of the light bulbs last longer than 150 hours. You choose a random sample of 14 bulbs of each brand. What decision should you make at the 5% significance level (alpha = 0.05)? 128 189 139 148 186 141 163 101 195 142 174 114 196 191 a. z = -2.576 b. t = +1.796 c. t = + 1.771 d. z = + 1.796
- For the independent-measures t statistic, what is the effect of increasing the difference between sample means? a. an increase in the likelihood of rejecting H0 and an increase in measures of effect size b. an increase in the likelihood of rejecting H0 and a decrease in measures of effect size c. a decrease in the likelihood of rejecting H0 and an increase in measures of effect size d. decrease in the likelihood of rejecting H0 and a decrease in measures of effect sizeIt has been claimed that at a university at least 40% of the students live on campus. In a random sample of 250 students, 90 were found to live on campus. What is the test value for testing the claim at a=.02? O A. - 2.33 B. 1.32 O C. -1.32 O D. - 1.29Suppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x = 101.13, y = 103.5, r=0.867, P-value = 0.000, and y = 6.25 +0.96x, where x represents the IQ score of the younger child. Find the best predicted value of y given that the younger child has an IQ of 101? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of ŷ is. (Round to two decimal places as needed.)
- Is the proportion of wildfires caused by humans in the south different from the proportion of wildfires caused by humans in the west? 372 of the 563 randomly selected wildfires looked at in the south were caused by humans while 372 of the 521 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the a 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: Select an answerv Select an answerv Select an answerv (please enter a decimal) H: Select an answerv Select an answerv Select an answerv (Please enter a decimal) C. The test statistic ?v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? a f. Based on this, we should Select an answerv the null hypothesis. g. Thus, the final conclusion is that ... O The results are statistically insignificant conclude that the population proportion from the…Suppose a study reported that the average persin watched 3.37 hours of television per day. a random sample of 15 people gave the number of hours of television watched per day shown below. at the 1% significance level, do the data provide sufficent evidence to conclude that the amount of television watched per day last year by the average person is greater than the value reported in the study? what is the test statistic value for this problem? a.0.28 b.-38 c.none of the above d. 0.58 e.-4.295 f..04 g. 1.94 . the proper conclusion for this problem is? a. reject the null hypothesis we have sufficent evidence to prove the average number of hours people watch tv is more than 3.37 hours. b. Do not reject the null hypothesis we have sufficient evidence to prove the average number of hours of TV watched is greater than 3.37 hours c. Reject the null hypothesis and claim the average number of hours people watch TV is less than 3.37 because the P value is near zero d. Do not reject the null…In a random sample of 925 plain M&M's, 19% were blue. Use a 0.01 significance level to test the claim of Mars, Inc. that 24% of its plain M&M candies are blue. a. Define the parameter A. p = The proportion of all M&M's that are blue B. mu = The proportion of all M&M's that are blue C. mu = The mean number of all M&M's that are blue D. p = The proportion of all M&M's that are not blue b. State the null and alternative hypotheses A. Upper H 0 : p greater than 0.24 Upper H 1 : p equals 0.24 B. Upper H 0 : p equals 0.19 Upper H 1 : p not equals 0.19 C. Upper H 0 : p equals 0.24 Upper H 1 : p not equals 0.24 D. Upper H 0 : mu not equals 0.24 Upper H 1 : mu equals 0.24 c. Calculate the test statistic. Which of these options is closest to the test statistic? A. negative 4.00 B. negative 3.65 C.…
- Is the proportion of wildfires caused by humans in the south higher than the proportion of wildfires caused by humans in the west? 380 of the 581 randomly selected wildfires looked at in the south were caused by humans while 318 of the 503 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the a = 0.10 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: Select an answer v Select an answer Select an answer v (please enter a decimal) Hj: Select an answer Select an answer vSelect an answer v (Please enter a decimal) c. The test statistic ? v (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? a f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... |the null hypothesis. O The results are statistically significant at a = 0.10, so there is sufficient evidence to…Is the proportion of wildfires caused by humans in the south higher than the proportion of wildfires caused by humans in the west? 348 of the 574 randomly selected wildfires looked at in the south were caused by humans while 272 of the 518 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: Select an answer Select an answer Select an answer (please enter a decimal) H₁: Select an answer Select an answer Select an answer (Please enter a decimal) = c. The test statistic ? ◊ your answer to 3 decimal places.) (please showA veterinarian is interested in researching the proportion of men and women cat owners and believes that the proportion of men cat owners is significantly different than the proportion of women cat owners. The veterinarian decides to obtain two independent samples of men and women cat owners and finds from one sample of 60 men, 35% owned cats. In the second sample of 80 women, 60% owned cats. Test the veterinarian's belief at the a = significance level. Preliminary: a. Is it safe to assume that nmen 5% of all men and nwomen 5% of all women? 0.05 Yes No b. Verify np (1 - p) ≥ 10. Round your answer to one decimal place. np (1 − p) nmen = nwomen (1 - p) Test the claim: = a. Determine the null and alternative hypotheses. Ho: Pmen? Pwomen Ha Pmen ? Pwomen b. The hypothesis test is right-tailed left-tailed two-tailed c. Determine the test statistic. Round to two decimal places. z = d. Find the p-value. Round to four decimal places. p-value e. Make a decision. O Fail to reject the null…