Suppose that in a certain town with a population of 5000 households, 3000 of the households have cell phones, 2000 have computers at home, and 1500 have both cell phones and computers. A household in the town is selected at random. Let P be the event that the household has a cell phone and C be the event that the household has a computer. What is the probability that the selected household owns a cell phone or a computer? O P(PNC) = 3000 2000 5000 5000 O P(PUC) = 3000 2000 5000 5000 O P(P C) = 3000 2000 1500 5000 5000 5000 O P(PUC) = 3000 2000 1500 5000 5000 5000

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Suppose that in a certain town with a population of 5000 households,
3000 of the households have cell phones,
2000 have computers at home, and
1500 have both cell phones and computers.
A household in the town is selected at random.
Let P be the event that the household has a cell phone and C be the event that the household
has a computer.
What is the probability that the selected household owns a cell phone or a computer?
O P(PnC) =
3000
2000
5000
5000
O P(PUC) =
3000
2000
%3D
5000
5000
O P(PNC) =
3000
2000
1500
%3D
|
5000
5000
5000
O P(PUC) =
3000
2000
1500
5000
5000
5000
Transcribed Image Text:Suppose that in a certain town with a population of 5000 households, 3000 of the households have cell phones, 2000 have computers at home, and 1500 have both cell phones and computers. A household in the town is selected at random. Let P be the event that the household has a cell phone and C be the event that the household has a computer. What is the probability that the selected household owns a cell phone or a computer? O P(PnC) = 3000 2000 5000 5000 O P(PUC) = 3000 2000 %3D 5000 5000 O P(PNC) = 3000 2000 1500 %3D | 5000 5000 5000 O P(PUC) = 3000 2000 1500 5000 5000 5000
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