Suppose that f(x, y) = x + 4y on the domain D = {(x, y) | 1 ≤ x ≤ 2, x² ≤ y ≤ 4}. D a Then the double integral of f(x, y) over Dis f(x, y)dady D =

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5.2.1

**Double Integral in a Bounded Region**

Suppose that \( f(x, y) = x + 4y \) on the domain \( D = \{(x, y) \mid 1 \leq x \leq 2, x^2 \leq y \leq 4\} \).

A graph is provided showing the region \( D \), which appears as a triangular area on the xy-plane. It is bounded as follows:
- The left boundary is \( x = 1 \).
- The right boundary is \( x = 2 \).
- The lower boundary is defined by the curve \( y = x^2 \).
- The upper boundary is the line \( y = 4 \).

The double integral of \( f(x, y) \) over the domain \( D \) is given by:

\[
\int \int_{D} f(x, y) \, dx \, dy = \text{[Exact Integral Value]}
\]

To evaluate this integral, set up iterated integrals according to the given boundaries and solve accordingly.
Transcribed Image Text:**Double Integral in a Bounded Region** Suppose that \( f(x, y) = x + 4y \) on the domain \( D = \{(x, y) \mid 1 \leq x \leq 2, x^2 \leq y \leq 4\} \). A graph is provided showing the region \( D \), which appears as a triangular area on the xy-plane. It is bounded as follows: - The left boundary is \( x = 1 \). - The right boundary is \( x = 2 \). - The lower boundary is defined by the curve \( y = x^2 \). - The upper boundary is the line \( y = 4 \). The double integral of \( f(x, y) \) over the domain \( D \) is given by: \[ \int \int_{D} f(x, y) \, dx \, dy = \text{[Exact Integral Value]} \] To evaluate this integral, set up iterated integrals according to the given boundaries and solve accordingly.
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